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Consider the series RLC bandpass filter shown in (Figure 1). The filter has a quality of 2 and a center frequency of 8 kHz. The input to the filter is v; (t) = 17 cos wt V. Suppose that C = 5 nF. Part A What is the voltage drop across the series combination of the inductor and capacitor when w= wo? VLC (t) =0 V ViC (t) = 17 cos(16,000xt) V VLC (t) = 12.02 cos(16,000xt + 45°) V VLC (t) = 12.02 cos(16,000rt – 45°) V Figure < 1 of 1 > Submit Request Answer

Consider the series RLC bandpass filter shown in (Figure 1). The filter has a quality of 2 and a center frequency of 8 kHz. The input to the filter is v; (t) = 17 cos wt V. Suppose that C = 5 nF. Part A What is the voltage drop across the series combination of the inductor and capacitor when w= wo? VLC (t) =0 V ViC (t) = 17 cos(16,000xt) V VLC (t) = 12.02 cos(16,000xt + 45°) V VLC (t) = 12.02 cos(16,000rt – 45°) V Figure < 1 of 1 > Submit Request Answer

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Solve Part A

Consider the series RLC bandpass filter shown in (Figure 1). The filter has a quality of 2 and a center frequency of 8 kHz. The input to the filter is v; (t) = 17 cos wt V. Suppose that C = 5 nF. Part A What is the voltage drop across the series combination of the inductor and capacitor when w= wo? VLC (t) =0 V ViC (t) = 17 cos(16,000xt) V VLC (t) = 12.02 cos(16,000xt + 45°) V VLC (t) = 12.02 cos(16,000rt – 45°) V Figure < 1 of 1 > Submit Request Answer
Transcribed Image Text:Consider the series RLC bandpass filter shown in (Figure 1). The filter has a quality of 2 and a center frequency of 8 kHz. The input to the filter is v; (t) = 17 cos wt V. Suppose that C = 5 nF. Part A What is the voltage drop across the series combination of the inductor and capacitor when w= wo? VLC (t) =0 V ViC (t) = 17 cos(16,000xt) V VLC (t) = 12.02 cos(16,000xt + 45°) V VLC (t) = 12.02 cos(16,000rt – 45°) V Figure < 1 of 1 > Submit Request Answer
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