Consider the series Answer: L = n=1 5" (n+1)4²n+1* Evaluate the the following limit. If it is infinite, type "infinity" or "inf". If it does not exist, type "DNE". lim n-00 an+1 an = L What can you say about the series using the Ratio Test? Answer "Convergent", "Divergent", or "Inconclusive". Answer: Convergent Determine whether the series is absolutely convergent, conditionally convergent, or divergent. Answer "Absolutely Convergent", "Conditionally Convergent", or "Divergent". Answer: Absolutely Convergent

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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26.
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Consider the series
Answer: L:
=
∞
n=1
5n
(n+1)4²n+1°
Evaluate the the following limit. If it is infinite, type "infinity" or "inf". If it does not exist, type "DNE".
lim
n→∞
an+1
an
-
L
What can you say about the series using the Ratio Test? Answer "Convergent", "Divergent", or "Inconclusive".
Answer: Convergent
< Previous
Determine whether the series is absolutely convergent, conditionally convergent, or divergent. Answer "Absolutely Convergent", "Conditionally
Convergent", or "Divergent".
Answer: Absolutely Convergent
Transcribed Image Text:26. Practice similar Help me with this Consider the series Answer: L: = ∞ n=1 5n (n+1)4²n+1° Evaluate the the following limit. If it is infinite, type "infinity" or "inf". If it does not exist, type "DNE". lim n→∞ an+1 an - L What can you say about the series using the Ratio Test? Answer "Convergent", "Divergent", or "Inconclusive". Answer: Convergent < Previous Determine whether the series is absolutely convergent, conditionally convergent, or divergent. Answer "Absolutely Convergent", "Conditionally Convergent", or "Divergent". Answer: Absolutely Convergent
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