Consider the sequence x[n] = [-3, 0, –1, {10}, 1, 0, 3], where the number in {·} corresponds to n = 0. Write down an expression for the phase spectrum ZX (w). your answer must be in cos and/or sin terms. Is the phase spectrum even or odd?

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### Understanding Phase Spectrum of a Sequence

Consider the sequence \( x[n] = [-3, 0, -1, \{10\}, 1, 0, 3] \), where the number in \( \{ \cdot \} \) corresponds to \( n = 0 \).

**Task:**

1. **Expression for the Phase Spectrum:**
   Write down an expression for the phase spectrum \( \angle X(\omega) \). Your answer must be in cos and/or sin terms.

2. **Properties of Phase Spectrum:**
   Is the phase spectrum even or odd?

### Step-by-Step Solution

#### 1. Expression for the Phase Spectrum \( \angle X(\omega) \)

The phase spectrum of a sequence \( x[n] \) is given by the argument (angle) of the Discrete-Time Fourier Transform (DTFT) of \( x[n] \). The DTFT of \( x[n] \) is defined as:

\[ 
X(\omega) = \sum_{n=-\infty}^{\infty} x[n] e^{-j\omega n}
\]

In this case, since \( x[n] \) is a finite sequence, the sum becomes finite. Substituting \( x[n] \):

\[
x[n] = 
\begin{cases} 
-3 & \text{for } n = -3 \\
0 & \text{for } n = -2 \\
-1 & \text{for } n = -1 \\
10 & \text{for } n = 0 \\
1 & \text{for } n = 1 \\
0 & \text{for } n = 2 \\
3 & \text{for } n = 3
\end{cases}
\]

So,

\[
X(\omega) = -3e^{j3\omega} + 0 \cdot e^{j2\omega} - e^{j\omega} + 10 + e^{-j\omega} + 0 \cdot e^{-j2\omega} + 3e^{-j3\omega}
\]

Combining terms:

\[
X(\omega) = 10 + 3e^{-j3\omega} - e^{j\omega} + e^{-j\omega} - 3e^{j3\omega}
\]

To express \(
Transcribed Image Text:### Understanding Phase Spectrum of a Sequence Consider the sequence \( x[n] = [-3, 0, -1, \{10\}, 1, 0, 3] \), where the number in \( \{ \cdot \} \) corresponds to \( n = 0 \). **Task:** 1. **Expression for the Phase Spectrum:** Write down an expression for the phase spectrum \( \angle X(\omega) \). Your answer must be in cos and/or sin terms. 2. **Properties of Phase Spectrum:** Is the phase spectrum even or odd? ### Step-by-Step Solution #### 1. Expression for the Phase Spectrum \( \angle X(\omega) \) The phase spectrum of a sequence \( x[n] \) is given by the argument (angle) of the Discrete-Time Fourier Transform (DTFT) of \( x[n] \). The DTFT of \( x[n] \) is defined as: \[ X(\omega) = \sum_{n=-\infty}^{\infty} x[n] e^{-j\omega n} \] In this case, since \( x[n] \) is a finite sequence, the sum becomes finite. Substituting \( x[n] \): \[ x[n] = \begin{cases} -3 & \text{for } n = -3 \\ 0 & \text{for } n = -2 \\ -1 & \text{for } n = -1 \\ 10 & \text{for } n = 0 \\ 1 & \text{for } n = 1 \\ 0 & \text{for } n = 2 \\ 3 & \text{for } n = 3 \end{cases} \] So, \[ X(\omega) = -3e^{j3\omega} + 0 \cdot e^{j2\omega} - e^{j\omega} + 10 + e^{-j\omega} + 0 \cdot e^{-j2\omega} + 3e^{-j3\omega} \] Combining terms: \[ X(\omega) = 10 + 3e^{-j3\omega} - e^{j\omega} + e^{-j\omega} - 3e^{j3\omega} \] To express \(
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