Consider the second order equation below. Find a recursion equation for the coefficients of the pow series solution. Express the coefficient an+1 in terms of n and an. −2xy"+(2x − 3)y'+5y = 0 [Note: complete the recursion equation by only entering the function in n that is multiplied by an produce an+1 for all n ≥ 0.] an+1 = ·an; n ≥0

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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**Problem Statement:**

Consider the second order equation below. Find a recursion equation for the coefficients of the power series solution. Express the coefficient \( a_{n+1} \) in terms of \( n \) and \( a_n \).

\[
-2xy'' + (2x - 3)y' + 5y = 0
\]

**Note:** Complete the recursion equation by only entering the function in \( n \) that is multiplied by \( a_n \) to produce \( a_{n+1} \) for all \( n \geq 0 \.

\[ 
a_{n+1} = \boxed{\phantom{answer}} \cdot a_n; \quad n \geq 0 
\]
Transcribed Image Text:**Problem Statement:** Consider the second order equation below. Find a recursion equation for the coefficients of the power series solution. Express the coefficient \( a_{n+1} \) in terms of \( n \) and \( a_n \). \[ -2xy'' + (2x - 3)y' + 5y = 0 \] **Note:** Complete the recursion equation by only entering the function in \( n \) that is multiplied by \( a_n \) to produce \( a_{n+1} \) for all \( n \geq 0 \. \[ a_{n+1} = \boxed{\phantom{answer}} \cdot a_n; \quad n \geq 0 \]
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The question says n>0 but your solution says n>1.

Is this the correct answer for the problem ? It asks for n>0.

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can this be done by a person?

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