Consider the sample of 106 body temperatures. Assume that the standard deviation of the population is known to be 0.62°F. Use a 0.05 significance level to test the claim that the mean body temperature of the population is equal to 98.6°F, as is commonly believed. Find the statistic, p-value and the critical value (or values). Is there sufficient evidence to conclude that the common belief is wrong? (This is one question but I don't know if it still counts as just one in bartleby I would not mind an anwser on part of the question and asking more)Data:Body Temperature (°F)98.698.698.098.099.098.498.498.498.498.698.698.898.697.097.098.897.697.798.898.098.098.398.597.398.797.498.998.699.597.597.397.698.299.698.799.498.298.098.698.697.298.498.698.298.097.898.098.498.698.697.899.096.597.698.096.997.697.197.998.497.398.097.597.698.298.598.898.797.898.097.197.499.498.498.698.498.598.698.398.798.899.198.697.998.898.098.798.598.998.498.697.197.998.898.797.698.299.297.898.098.497.898.497.498.097.0 JBody Temperature (°F)1298.6398.6Body TemperatureNull hypothesisAlternative hypothesis498.098.0Significance levelSample mean99.00.05798.4898.4Z-statistic98.4Critical value (or values)1098.4p-value1198.6Conclusion1298.61398.81498.6;Show any intermediate calculations around here1597.01697.01798.81897.61997.72098.82198.02298.0;2398.32498.52597.32698.72797.428ag a!

Name: Consider the sample of 106 body temperatures. Assume that the standard
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Description: Consider the sample of 106 body temperatures. Assume that the standard deviation of the population is known to be 0.62°F. Use a 0.05 significance level to test the claim that the mean body temperature of the population is equal to 98.6°F, as is commo

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

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Problem 1P

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Consider the sample of 106 body temperatures. Assume that the standard deviation of the population is known to be 0.62°F. Use a 0.05 significance level to test the claim that the mean body temperature of the population is equal to 98.6°F, as is commonly believed. Find the statistic, p-value and the critical value (or values). Is there sufficient evidence to conclude that the common belief is wrong?

(This is one question but I don't know if it still counts as just one in bartleby I would not mind an anwser on part of the question and asking more)

Data:

Body Temperature (°F)
98.6
98.6
98.0
98.0
99.0
98.4
98.4
98.4
98.4
98.6
98.6
98.8
98.6
97.0
97.0
98.8
97.6
97.7
98.8
98.0
98.0
98.3
98.5
97.3
98.7
97.4
98.9
98.6
99.5
97.5
97.3
97.6
98.2
99.6
98.7
99.4
98.2
98.0
98.6
98.6
97.2
98.4
98.6
98.2
98.0
97.8
98.0
98.4
98.6
98.6
97.8
99.0
96.5
97.6
98.0
96.9
97.6
97.1
97.9
98.4
97.3
98.0
97.5
97.6
98.2
98.5
98.8
98.7
97.8
98.0
97.1
97.4
99.4
98.4
98.6
98.4
98.5
98.6
98.3
98.7
98.8
99.1
98.6
97.9
98.8
98.0
98.7
98.5
98.9
98.4
98.6
97.1
97.9
98.8
98.7
97.6
98.2
99.2
97.8
98.0
98.4
97.8
98.4
97.4
98.0
97.0

J
Body Temperature (°F)
1
2
98.6
3
98.6
Body Temperature
Null hypothesis
Alternative hypothesis
4
98.0
98.0
Significance level
Sample mean
99.0
0.05
7
98.4
8
98.4
Z-statistic
98.4
Critical value (or values)
10
98.4
p-value
11
98.6
Conclusion
12
98.6
13
98.8
14
98.6;
Show any intermediate calculations around here
15
97.0
16
97.0
17
98.8
18
97.6
19
97.7
20
98.8
21
98.0
22
98.0;
23
98.3
24
98.5
25
97.3
26
98.7
27
97.4
28
ag a!

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

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