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Consider the roots (zeros) of f(x) = a³ – 4x + 1. 7+ 6 5 3 -4 -3 -2 -1 3 -1 -2 - -3 - -4 -5- We will see that small changes in the choice of r, produce different roots, or none at al For each r. given, state the root (zero) of f(x) to which the algorithm converges, or w DNE if it does not converge. round to 3 decimal places If x, = 1.85, then Newton's Method converges to: # = If x, = 1.7, then Newton's Method converges to: æ = If x, = 1.55, then Newton's Method converges to: x = 2.

Consider the roots (zeros) of f(x) = a³ – 4x + 1. 7+ 6 5 3 -4 -3 -2 -1 3 -1 -2 - -3 - -4 -5- We will see that small changes in the choice of r, produce different roots, or none at al For each r. given, state the root (zero) of f(x) to which the algorithm converges, or w DNE if it does not converge. round to 3 decimal places If x, = 1.85, then Newton's Method converges to: # = If x, = 1.7, then Newton's Method converges to: æ = If x, = 1.55, then Newton's Method converges to: x = 2.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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1 Consider the roots (zeros) of f(x) =a³ – 4x + 1. 7+ 6- 5- 4- -4 -3 -2 3 -1- -2- -3 -4 -5+ We will see that small changes in the choice of x, produce different roots, or none at all. For each x, given, state the root (zero) of f(x) to which the algorithm converges, or write DNE if it does not converge. round to 3 decimal places If x, = 1.85, then Newton's Method converges to: x = If r. 1.7, then Newton's Method converges to: * = If To 1.55, then Newton's Method converges to: 2 = 3.
Transcribed Image Text:1 Consider the roots (zeros) of f(x) =a³ – 4x + 1. 7+ 6- 5- 4- -4 -3 -2 3 -1- -2- -3 -4 -5+ We will see that small changes in the choice of x, produce different roots, or none at all. For each x, given, state the root (zero) of f(x) to which the algorithm converges, or write DNE if it does not converge. round to 3 decimal places If x, = 1.85, then Newton's Method converges to: x = If r. 1.7, then Newton's Method converges to: * = If To 1.55, then Newton's Method converges to: 2 = 3.
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