Consider the RL circuit below where Vs=5sin(3t), L=2H, and R=6 . The switch has been open a long time before it is closed at time t=0. a. What is the governing equation for the current through the inductor, i(t)? What is the initial condition? b. Find the form of the complementary solution, ic(t). Remember that the constant of integration should not be evaluated at this time. c. Find the particular solution. d. Find the complete solution for i(t) by superposing the particular and complementary solutions and applying the initial condition. e. Plot the voltage v(t) vs. time. +1 SW Vs ами L v(t) R

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
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**Transcription for Educational Website:**

Title: Analyzing an RL Circuit with a Time-Varying Source

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**Problem Explanation:**

Consider the RL circuit below where \( V_s = 5\sin(3t) \), \( L = 2H \), and \( R = 6 \, \Omega \). The switch has been open a long time before it is closed at time \( t=0 \).

**Tasks:**

a. What is the governing equation for the current through the inductor, \( i(t) \)? What is the initial condition?

b. Find the form of the complementary solution, \( i_c(t) \). Remember that the constant of integration should not be evaluated at this time.

c. Find the particular solution.

d. Find the complete solution for \( i(t) \) by superposing the particular and complementary solutions and applying the initial condition.

e. Plot the voltage \( v(t) \) vs. time.

---

**Circuit Diagram Explanation:**

The circuit schematic shows:

- A switch (SW) which is initially open and then closed at \( t=0 \).
- An AC voltage source \( V_s = 5\sin(3t) \) connected in series.
- An inductor (L) with an inductance of \( 2 \, H \).
- A resistor (R) with a resistance of \( 6 \, \Omega \).
- The voltage across the resistor-inductor combination is labeled as \( v(t) \).

The task involves solving the differential equation for a given RL circuit with a sinusoidal source and determining the solutions under specific initial conditions.
Transcribed Image Text:**Transcription for Educational Website:** Title: Analyzing an RL Circuit with a Time-Varying Source --- **Problem Explanation:** Consider the RL circuit below where \( V_s = 5\sin(3t) \), \( L = 2H \), and \( R = 6 \, \Omega \). The switch has been open a long time before it is closed at time \( t=0 \). **Tasks:** a. What is the governing equation for the current through the inductor, \( i(t) \)? What is the initial condition? b. Find the form of the complementary solution, \( i_c(t) \). Remember that the constant of integration should not be evaluated at this time. c. Find the particular solution. d. Find the complete solution for \( i(t) \) by superposing the particular and complementary solutions and applying the initial condition. e. Plot the voltage \( v(t) \) vs. time. --- **Circuit Diagram Explanation:** The circuit schematic shows: - A switch (SW) which is initially open and then closed at \( t=0 \). - An AC voltage source \( V_s = 5\sin(3t) \) connected in series. - An inductor (L) with an inductance of \( 2 \, H \). - A resistor (R) with a resistance of \( 6 \, \Omega \). - The voltage across the resistor-inductor combination is labeled as \( v(t) \). The task involves solving the differential equation for a given RL circuit with a sinusoidal source and determining the solutions under specific initial conditions.
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