Consider the reversible, exothermic, gas phase reaction A + B 2C in a flow reactor. The reactants enter at 300 K, and the maximum operating temperature is 600 K. FAO = FBO = 20 mol/min. Kc =5 at 450 K, KA = 0.8 L/mol min at 500 K, EA = 8,000 cal/mol, vo = 2 L/min. Pressure drop is negligible. (Some answers are given in blue. You must show full work that gives these answers to obtain full credit) Species A H (273 K) -12 kcal/mol Ср 25 cal/mol K B -16 kcal/mol 25 cal/mol.K C -25 kcal/mol 25 cal/mol.K (AHRx=-22 kcal/mol) a) Calculate the conversion and temperature in a 50 L adiabatic CSTR. Hint: If you are having problems getting Polymath to converge on a solution, use initial guesses for X and T that both fall on the same Energy Balance line. (XA = 0.388) (b) Calculate the conversion and temperature leaving a 50 L adiabatic PFR. Plot the XA, Xe, and temperature as a function of reactor volume. (X4 = 0.390) c) If you have interstage heat exchange between series reactors to decrease the temperature back to 300 K, calculate the number of 50 L CSTRS needed to obtain a conversion of at least 75%. What are the conversion and temperature leaving each reactor? (3 reactors) d) Repeat #3 for the case where you have 25 L PFRs in series with interstage cooling to reach a conversion of at least 80%. (5 reactors) e) Repeat #4 for the case where you have series PFRS with enough volume to reach 99.9% of the equilibrium conversion in each reactor. (3 reactors) f) Calculate the reactor volume and how much heat must be added (in kW) to get a conversion of 80% in a single (non-adiabatic) CSTR if U = 300 cal/min dm² K, A = 30 dm², T₁ = 325 K (assume essentially constant due to high heat transfer fluid flow). (V= 178.4 L, Q = 20.5 kW) 9 Plot XA, Xe, T, and Ta down the length of a 500 L PFR with co-current heat exchange if Ua = 30 cal/L min K, TAO = 325 K, heat transfer fluid: me = 40 mol/min and Cpc = 30 cal/mol·K. (X = 0.617 at the exit) h) Repeat part #7 for a PFR with counter-current heat exchange. (X4 = 0.669 at the exit) i) Compare conversion, outlet temperature, and shape of the curves in #7 and #8. Discuss any differences.

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
Question

Please help me with all parts. Answers have been provided for certain steps

Consider the reversible, exothermic, gas phase reaction A + B 2C in a flow reactor. The
reactants enter at 300 K, and the maximum operating temperature is 600 K. FAO = FBO = 20
mol/min. Kc =5 at 450 K, KA = 0.8 L/mol min at 500 K, EA = 8,000 cal/mol, vo = 2 L/min.
Pressure drop is negligible. (Some answers are given in blue. You must show full work that gives
these answers to obtain full credit)
Species
A
H (273 K)
-12 kcal/mol
Ср
25 cal/mol K
B
-16 kcal/mol
25 cal/mol.K
C
-25 kcal/mol
25 cal/mol.K
(AHRx=-22 kcal/mol)
a) Calculate the conversion and temperature in a 50 L adiabatic CSTR. Hint: If you are having
problems getting Polymath to converge on a solution, use initial guesses for X and T that
both fall on the same Energy Balance line. (XA = 0.388)
(b) Calculate the conversion and temperature leaving a 50 L adiabatic PFR. Plot the XA, Xe, and
temperature as a function of reactor volume. (X4 = 0.390)
c) If you have interstage heat exchange between series reactors to decrease the temperature
back to 300 K, calculate the number of 50 L CSTRS needed to obtain a conversion of at least
75%. What are the conversion and temperature leaving each reactor? (3 reactors)
d) Repeat #3 for the case where you have 25 L PFRs in series with interstage cooling to reach a
conversion of at least 80%. (5 reactors)
e) Repeat #4 for the case where you have series PFRS with enough volume to reach 99.9% of
the equilibrium conversion in each reactor. (3 reactors)
f) Calculate the reactor volume and how much heat must be added (in kW) to get a conversion
of 80% in a single (non-adiabatic) CSTR if U = 300 cal/min dm² K, A = 30 dm², T₁ = 325 K
(assume essentially constant due to high heat transfer fluid flow). (V= 178.4 L, Q = 20.5
kW)
9 Plot XA, Xe, T, and Ta down the length of a 500 L PFR with co-current heat exchange if Ua =
30 cal/L min K, TAO = 325 K, heat transfer fluid: me = 40 mol/min and Cpc = 30 cal/mol·K.
(X = 0.617 at the exit)
h) Repeat part #7 for a PFR with counter-current heat exchange. (X4 = 0.669 at the exit)
i) Compare conversion, outlet temperature, and shape of the curves in #7 and #8. Discuss any
differences.
Transcribed Image Text:Consider the reversible, exothermic, gas phase reaction A + B 2C in a flow reactor. The reactants enter at 300 K, and the maximum operating temperature is 600 K. FAO = FBO = 20 mol/min. Kc =5 at 450 K, KA = 0.8 L/mol min at 500 K, EA = 8,000 cal/mol, vo = 2 L/min. Pressure drop is negligible. (Some answers are given in blue. You must show full work that gives these answers to obtain full credit) Species A H (273 K) -12 kcal/mol Ср 25 cal/mol K B -16 kcal/mol 25 cal/mol.K C -25 kcal/mol 25 cal/mol.K (AHRx=-22 kcal/mol) a) Calculate the conversion and temperature in a 50 L adiabatic CSTR. Hint: If you are having problems getting Polymath to converge on a solution, use initial guesses for X and T that both fall on the same Energy Balance line. (XA = 0.388) (b) Calculate the conversion and temperature leaving a 50 L adiabatic PFR. Plot the XA, Xe, and temperature as a function of reactor volume. (X4 = 0.390) c) If you have interstage heat exchange between series reactors to decrease the temperature back to 300 K, calculate the number of 50 L CSTRS needed to obtain a conversion of at least 75%. What are the conversion and temperature leaving each reactor? (3 reactors) d) Repeat #3 for the case where you have 25 L PFRs in series with interstage cooling to reach a conversion of at least 80%. (5 reactors) e) Repeat #4 for the case where you have series PFRS with enough volume to reach 99.9% of the equilibrium conversion in each reactor. (3 reactors) f) Calculate the reactor volume and how much heat must be added (in kW) to get a conversion of 80% in a single (non-adiabatic) CSTR if U = 300 cal/min dm² K, A = 30 dm², T₁ = 325 K (assume essentially constant due to high heat transfer fluid flow). (V= 178.4 L, Q = 20.5 kW) 9 Plot XA, Xe, T, and Ta down the length of a 500 L PFR with co-current heat exchange if Ua = 30 cal/L min K, TAO = 325 K, heat transfer fluid: me = 40 mol/min and Cpc = 30 cal/mol·K. (X = 0.617 at the exit) h) Repeat part #7 for a PFR with counter-current heat exchange. (X4 = 0.669 at the exit) i) Compare conversion, outlet temperature, and shape of the curves in #7 and #8. Discuss any differences.
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