**Problem Statement:**Consider the relation `employee(name, supervisorName, sex)` with `name` as the primary key. `supervisorName` contains the name of the supervisor of every employee. What is the result of the following Tuple Relational Calculus expression? (Note: Subordinates are employees working for a supervisor.)**Tuple Relational Calculus Expression:**\[{e.name | employee(e) ∧ (∀x)[¬employee(x) ∨ x.supervisorName ≠ e.name ∨ x.sex = "male"] }\]**Options:**1. Names of employees with a male supervisor2. Names of employees with a female supervisor3. Names of employees with no immediate male subordinates4. Names of employees with no immediate female subordinates**Explanation of the Tuple Relational Calculus Expression:**- The expression `{e.name | employee(e) ...}` signifies that we are extracting the `name` field from the `employee` relation, denoted by `e`.- The expression `employee(e)` indicates that `e` is a tuple within the `employee` relation.- The condition `(∀x)[¬employee(x) ∨ x.supervisorName ≠ e.name ∨ x.sex = "male"]` entails universal quantification over `x`, another tuple in the `employee` relation. - `¬employee(x)` means `x` is not an employee, which would trivially be false for existing employees. - `x.supervisorName ≠ e.name` ensures that `x` is not supervised by `e`. - `x.sex = "male"` allows `x` to be male. - This results in selecting employees `e` such that either: - There are no employees `x` under `e` as their supervisor, or - All subordinates `x` under `e` are male.Thus, the relation describes employees who have no immediate female subordinates.**Correct Answer:**- **Names of employees with no immediate female subordinates**

Answered: Image /qna-images/answer/4ec0759b-c5e2-4302-a405-721032b48b71.jpg

Consider the relation employee(name, supervisorName, sex) with name as the primary key. supervisorName contains the name of the upervisor of every employee. What is the result of the following Tuple Relational Calculus expression? (Note: Subordinates are mployees working for a supervisor.) e.name employee (e)^ (vx)[-employee (x) v x.supervisorName = e.name v x.sex = O Names of employees with a male supervisor O Names of employees with a female supervisor O Names of employees with no immediate male subordinates O Names of employees with no immediate female subordinates "male"]}

Consider the relation employee(name, supervisorName, sex) with name as the primary key. supervisorName contains the name of the upervisor of every employee. What is the result of the following Tuple Relational Calculus expression? (Note: Subordinates are mployees working for a supervisor.) e.name employee (e)^ (vx)[-employee (x) v x.supervisorName = e.name v x.sex = O Names of employees with a male supervisor O Names of employees with a female supervisor O Names of employees with no immediate male subordinates O Names of employees with no immediate female subordinates "male"]}

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

**Problem Statement:**

Consider the relation `employee(name, supervisorName, sex)` with `name` as the primary key. `supervisorName` contains the name of the supervisor of every employee. What is the result of the following Tuple Relational Calculus expression? (Note: Subordinates are employees working for a supervisor.)

**Tuple Relational Calculus Expression:**

\[{e.name | employee(e) ∧ (∀x)[¬employee(x) ∨ x.supervisorName ≠ e.name ∨ x.sex = "male"] }\]

**Options:**
1. Names of employees with a male supervisor
2. Names of employees with a female supervisor
3. Names of employees with no immediate male subordinates
4. Names of employees with no immediate female subordinates

**Explanation of the Tuple Relational Calculus Expression:**

- The expression `{e.name | employee(e) ...}` signifies that we are extracting the `name` field from the `employee` relation, denoted by `e`.
- The expression `employee(e)` indicates that `e` is a tuple within the `employee` relation.
- The condition `(∀x)[¬employee(x) ∨ x.supervisorName ≠ e.name ∨ x.sex = "male"]` entails universal quantification over `x`, another tuple in the `employee` relation.
- `¬employee(x)` means `x` is not an employee, which would trivially be false for existing employees.
- `x.supervisorName ≠ e.name` ensures that `x` is not supervised by `e`.
- `x.sex = "male"` allows `x` to be male.

- This results in selecting employees `e` such that either:
- There are no employees `x` under `e` as their supervisor, or
- All subordinates `x` under `e` are male.

Thus, the relation describes employees who have no immediate female subordinates.

**Correct Answer:**

- **Names of employees with no immediate female subordinates**

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