Consider the region bounded by the curve y = √√x + 1, the line y = 2 and the y-axis. Setup an integral with respect to x that gives the area of the region. Area = f(x) dx where f(x)= 2-(sqrt (x+1)) , a= Area = 8/3 -1 Setup an integral with respect to y that gives the area of the region. Area = g(y) dy where g(y)= y^2 Evaluate either (or both) of these integrals to find the area of the region. , C = 0 ,b= 3 , d = 2 You may want to look at this graph on desmos: https://www.desmos.com/calculator/nbq23b3ezy

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Consider the region bounded by the curve y = √√x + 1, the line y = 2 and the y-axis.
Setup an integral with respect to x that gives the area of the region.
Area =
f(x) dx where ƒ(x)= 2-(sqrt (x+1))
"
a =
Setup an integral with respect to y that gives the area of the region.
Area =
g(y) dy where g(y)= y^2
Area = 8/3
-1
C = 0
Evaluate either (or both) of these integrals to find the area of the region.
"
"
b = 3
d = 2
You may want to look at this graph on desmos: https://www.desmos.com/calculator/nbq23b3ezy
Transcribed Image Text:Consider the region bounded by the curve y = √√x + 1, the line y = 2 and the y-axis. Setup an integral with respect to x that gives the area of the region. Area = f(x) dx where ƒ(x)= 2-(sqrt (x+1)) " a = Setup an integral with respect to y that gives the area of the region. Area = g(y) dy where g(y)= y^2 Area = 8/3 -1 C = 0 Evaluate either (or both) of these integrals to find the area of the region. " " b = 3 d = 2 You may want to look at this graph on desmos: https://www.desmos.com/calculator/nbq23b3ezy
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