Consider the reaction of solid PbO and gaseous NH3 to form solid Pb, nitrogen gas, and water vapor. The balanced chemical equation is 3 PbO(s) + 2 NH3(g) - 3 Pb(s) + N2(g) + 3 H20(g). How many grams of NH3 will be required to react with 32.7 grams of pbo based on the balanced chemical equation?

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Consider the reaction of solid PbO and gaseous NH3 to form solid Pb, nitrogen gas, and water vapor. The balanced chemical equation is 3 PbO(s) + 2 NH3(g) - 3 Pb(s) + N2(g) + 3 H20(g). How many grams of NH3 will be required to react with 32.7 grams of pbo based on the balanced chemical equation?
2:12
Question 8.d of 8
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The balanced chemical equation is 3 PbO(s) + 2 NH3(g) →
3 Pb(s) + N2(g) + 3 H20(g). How many grams of NH3 will
be required to react with 32.7
grams of Pb0 based on
the balanced chemical equation?
17.03
32.7
GPLO
STARTING AMOUNT
223.2
17.03 g NH3
2 mol NH3
32.7 g Pbo
1.66 g NH3
223.2 g PbO
3 g NH3
ADD FACTOR
DELETE
ANSWER
RESET
*( )
げ
17.03
643
g PbO/mol PbO
32.7
0.267
mol NH3
223.2
3
mol PbO
21.8
1.66
g Pbo
1
2.49
g NH3
2
g NH3/mol NH3
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Transcribed Image Text:2:12 Question 8.d of 8 Submit The balanced chemical equation is 3 PbO(s) + 2 NH3(g) → 3 Pb(s) + N2(g) + 3 H20(g). How many grams of NH3 will be required to react with 32.7 grams of Pb0 based on the balanced chemical equation? 17.03 32.7 GPLO STARTING AMOUNT 223.2 17.03 g NH3 2 mol NH3 32.7 g Pbo 1.66 g NH3 223.2 g PbO 3 g NH3 ADD FACTOR DELETE ANSWER RESET *( ) げ 17.03 643 g PbO/mol PbO 32.7 0.267 mol NH3 223.2 3 mol PbO 21.8 1.66 g Pbo 1 2.49 g NH3 2 g NH3/mol NH3 Tap here or pull up for additional resources
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