Consider the reaction of 75.0 mL of 0.350 M CSHSN (Kb = 1.7 x 10) with 100.0 mL of 0.419 M HCI. Write the net ionic equation for the reaction that takes place. CSH&N(aq) + H-(aq) → C«H»NH“(aq)

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Consider the reaction of 75.0 mL of 0.350 M CSHSN (Kb = 1.7 x 10) with
100.0 mL of 0.419 M HCI.
Write the net ionic equation for the reaction that takes place.
CSH»N(aq) + H-(aq) → C«H$NH¨(aq)
ロ?|□
3
3
8.
(s) || (1) (g) (aq)
H.O
H.O
OH
5.
4.
2.
+.
1.
Transcribed Image Text:Consider the reaction of 75.0 mL of 0.350 M CSHSN (Kb = 1.7 x 10) with 100.0 mL of 0.419 M HCI. Write the net ionic equation for the reaction that takes place. CSH»N(aq) + H-(aq) → C«H$NH¨(aq) ロ?|□ 3 3 8. (s) || (1) (g) (aq) H.O H.O OH 5. 4. 2. +. 1.
Expert Solution
Step 1

In the given reaction,  75.0 mL of 0.350 M C5H5N reacts with 100.0 mL of 0.419 M HCI. 

Kb = 1.7 x 10-9 


The net ionic equation for the reaction has to be determined.

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