Consider the reaction of 2-bromo-2-methylpropane with water, shown below, to answer the following question(s) CH3 CH3 H₂O H3C-C-OH + HBr H3CC-Br

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Question 11
**Title: Reaction Mechanism of 2-Bromo-2-methylpropane with Water**

**Introduction:**
This page explores the reaction of 2-bromo-2-methylpropane with water and provides a detailed analysis of the step-by-step mechanism. 

**Reaction Overview:**
Consider the reaction of 2-bromo-2-methylpropane with water, as represented below:

\[ \text{CH}_3 \text{CH}_3\text{C} - \text{CH}_3\text{Br} + \text{H}_2\text{O} \rightarrow \text{CH}_3\text{CH}_3\text{C} - \text{CH}_3\text{OH} + \text{HBr} \]

**Diagram 1: First Step of the Reaction**

The first step of this reaction is shown below:

![Step 1 Reaction](image_link)

\[ \text{CH}_3\text{CH}_3\text{C} - \text{CH}_3\text{Br} \leftrightarrow \text{CH}_3\text{CH}_3\text{C}^+ - \text{CH}_3 + \text{Br}^- \]

Where \( A \) represents the 2-bromo-2-methylpropane, and \( B \) represents the carbocation intermediate formed after the departure of the bromide ion.

**Diagram 2: Second and Third Steps of the Reaction**

The second and third steps of the reaction are shown below:

![Steps 2 and 3](image_link)

\[ \text{CH}_3\text{CH}_3\text{C}^+ - \text{CH}_3 + \text{H}_2\text{O} \leftrightarrow \text{CH}_3\text{CH}_3\text{C}\text{OH}_2^+ - \text{CH}_3 \rightarrow \text{CH}_3\text{CH}_3\text{C} - \text{CH}_3\text{OH} + \text{H}_3\text{O}^+ \]

**Mechanism Explanation with Electron Flow:**

- In **Diagram 1**, 2-bromo-2-methylpropane (**A**) undergoes heterolysis to form a tertiary carbocation (**
Transcribed Image Text:**Title: Reaction Mechanism of 2-Bromo-2-methylpropane with Water** **Introduction:** This page explores the reaction of 2-bromo-2-methylpropane with water and provides a detailed analysis of the step-by-step mechanism. **Reaction Overview:** Consider the reaction of 2-bromo-2-methylpropane with water, as represented below: \[ \text{CH}_3 \text{CH}_3\text{C} - \text{CH}_3\text{Br} + \text{H}_2\text{O} \rightarrow \text{CH}_3\text{CH}_3\text{C} - \text{CH}_3\text{OH} + \text{HBr} \] **Diagram 1: First Step of the Reaction** The first step of this reaction is shown below: ![Step 1 Reaction](image_link) \[ \text{CH}_3\text{CH}_3\text{C} - \text{CH}_3\text{Br} \leftrightarrow \text{CH}_3\text{CH}_3\text{C}^+ - \text{CH}_3 + \text{Br}^- \] Where \( A \) represents the 2-bromo-2-methylpropane, and \( B \) represents the carbocation intermediate formed after the departure of the bromide ion. **Diagram 2: Second and Third Steps of the Reaction** The second and third steps of the reaction are shown below: ![Steps 2 and 3](image_link) \[ \text{CH}_3\text{CH}_3\text{C}^+ - \text{CH}_3 + \text{H}_2\text{O} \leftrightarrow \text{CH}_3\text{CH}_3\text{C}\text{OH}_2^+ - \text{CH}_3 \rightarrow \text{CH}_3\text{CH}_3\text{C} - \text{CH}_3\text{OH} + \text{H}_3\text{O}^+ \] **Mechanism Explanation with Electron Flow:** - In **Diagram 1**, 2-bromo-2-methylpropane (**A**) undergoes heterolysis to form a tertiary carbocation (**
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