Consider the reaction, n+³ He He + y. Parta) Find the amount of energy transferred to the 4He, also called an a particle. Assume the reactants are initially at rest. Use the following atomic mass values when determining the total energy released: neutron 1.008665 u helium-3 3.016029 u helium-4 4.002603 u principle to solve this problem. It will be useful to use the mass of the You will need to use conservation of momentum a particle in the form 3727 MeV/c² for some parts of the problem. Ey=1 MeV
Nuclear Fission
Nuclear fission is a type of nuclear reaction in which heavier nuclei split into lighter nuclei by releasing a large quantity of energy. The elements like uranium-235 and plutonium-239 isotope undergo nuclear fission releasing energy. When nuclei undergo fission, some quantity of mass is lost. The lost mass is converted to nuclear energy. Nuclear fission reaction is used in nuclear power plants and atomic bombs. In nuclear power plants, nuclear reactors are used to generate electricity.
Endothermic Nuclear Reaction
A nuclear reaction can be described as a process where two atoms, or two nuclei or nucleus and subatomic particles such as a proton, neutron interact together, and a large amount of energy is produced and new elements are also produced.
Please solve both part a (in the image) and part b.
part b) Find the amount of energy transferred to the alpha particle (4He).
![**Nuclear Reaction Analysis**
**Consider the reaction:**
\[ n + ^3 \text{He} \rightarrow ^4 \text{He} + \gamma \]
**Part (a):** Find the amount of energy transferred to the \( ^4\text{He} \), also called an \( \alpha \) particle. Assume the reactants are initially at rest. Use the following atomic mass values when determining the total energy released:
- Neutron: 1.008665 u
- Helium-3: 3.016029 u
- Helium-4: 4.002603 u
You will need to use the conservation of momentum principle to solve this problem. It will be useful to use the mass of the \( \alpha \) particle in the form \( 3727 \text{ MeV}/c^2 \) for some parts of the problem.
\[
E_\gamma = \underline{\hspace{30pt}} \text{ MeV}
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