Consider the reaction CH₂O(g) = H₂(g) + CO(g). Exactly 3.4E-2 moles of CH₂O were injected into a 250 mL flask. At equilibrium, [CH₂O]=6.2E-2 M. What is Ke for this reaction?

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter16: Spontaneity Of Reaction
Section: Chapter Questions
Problem 102QAP: Consider the formation of HI(g) from H2(g) and I2(g). H2(g)+I2(g)2HI(g) For this reaction, K at 333C...
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Consider the reaction CH₂O(g) = H₂(g) + CO(g). Exactly 3.4E-2 moles of CH₂O were injected into a 250 mL flask. At equilibrium,
[CH₂O]=6.2E-2 M. What is Ke for this reaction?
ir notation (Uso Enotation and only 1 digit before decimal e.g. 2.5E5 for 2.5 x 10°)
Transcribed Image Text:Consider the reaction CH₂O(g) = H₂(g) + CO(g). Exactly 3.4E-2 moles of CH₂O were injected into a 250 mL flask. At equilibrium, [CH₂O]=6.2E-2 M. What is Ke for this reaction? ir notation (Uso Enotation and only 1 digit before decimal e.g. 2.5E5 for 2.5 x 10°)
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