Consider the reaction between barium and sulfur: Ba(s) + S(s) BaS(s) Both barium and sulfur also combine with oxygen to form barium oxide and sulfur dioxide. When 95.0 g of Ba react with 50.0 g of sulfur, only 65.15 g of Bas are obtained. Assuming 100% yield for the oxides, how many grams of BaO and SO2 are formed?
Consider the reaction between barium and sulfur: Ba(s) + S(s) BaS(s) Both barium and sulfur also combine with oxygen to form barium oxide and sulfur dioxide. When 95.0 g of Ba react with 50.0 g of sulfur, only 65.15 g of Bas are obtained. Assuming 100% yield for the oxides, how many grams of BaO and SO2 are formed?
Chemistry
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Chapter1: Chemical Foundations
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
Transcribed Image Text:Consider the reaction between barium and sulfur:
Ba(s) + S(s)
→ BaS(s)
Both barium and sulfur also combine with oxygen to form barium oxide and sulfur dioxide. When
95.0 g of Ba react with 50.0 g of sulfur, only 65.15 g of Bas are obtained. Assuming 100% yield for the
oxides, how many grams of Bao and SO2 are formed?
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