Consider the reaction at 298 K. Sn2*(aq) + 2FE3*(aq) Sn4*(aq) + - 2F22*(aq) E° = 0.617 V What is the value of E when [Sn2+] and [Fe3+] are equal to 0.50 M and [Sn4+] and [Fe2+] are equal to 0.10 M? RT Item equation/constant: E =E° - -InQ F = 96485 J/V mol e and R= 8.314 J/(mol K) nF O 0.069 V O 0.679 V O 0.658 V O 0.576 V

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Consider the reaction at 298 K.
Sn2*(aq) + 2Fe* (aq) Sn4*(aq) + 2FE2*(aq)
E° = 0.617 V
What is the value of E when [Sn2*] and [Fe3*] are equal to 0.50 M and [Sn4*] and [Fe2*] are equal to 0.10 M?
RT
E =E° -.
InQ
nF
Item equation/constant:
F = 96485 J/V mol e and R = 8.314 J/(mol K)
O 0.069 V
O 0.679 V
O 0.658 V
O 0.576 V
amstime
Transcribed Image Text:Consider the reaction at 298 K. Sn2*(aq) + 2Fe* (aq) Sn4*(aq) + 2FE2*(aq) E° = 0.617 V What is the value of E when [Sn2*] and [Fe3*] are equal to 0.50 M and [Sn4*] and [Fe2*] are equal to 0.10 M? RT E =E° -. InQ nF Item equation/constant: F = 96485 J/V mol e and R = 8.314 J/(mol K) O 0.069 V O 0.679 V O 0.658 V O 0.576 V amstime
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