Consider the reaction at 298 K. Sn2*(aq) + 2FE3*(aq) Sn4*(aq) + - 2F22*(aq) E° = 0.617 V What is the value of E when [Sn2+] and [Fe3+] are equal to 0.50 M and [Sn4+] and [Fe2+] are equal to 0.10 M? RT Item equation/constant: E =E° - -InQ F = 96485 J/V mol e and R= 8.314 J/(mol K) nF O 0.069 V O 0.679 V O 0.658 V O 0.576 V
Consider the reaction at 298 K. Sn2*(aq) + 2FE3*(aq) Sn4*(aq) + - 2F22*(aq) E° = 0.617 V What is the value of E when [Sn2+] and [Fe3+] are equal to 0.50 M and [Sn4+] and [Fe2+] are equal to 0.10 M? RT Item equation/constant: E =E° - -InQ F = 96485 J/V mol e and R= 8.314 J/(mol K) nF O 0.069 V O 0.679 V O 0.658 V O 0.576 V
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter16: Spontaneity Of Reaction
Section: Chapter Questions
Problem 61QAP: Consider the reaction CO(g)+H2O(g)CO2(g)+H2(g) Use the appropriate tables to calculate (a) G at 552C...
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![Consider the reaction at 298 K.
Sn2*(aq) + 2Fe* (aq) Sn4*(aq) + 2FE2*(aq)
E° = 0.617 V
What is the value of E when [Sn2*] and [Fe3*] are equal to 0.50 M and [Sn4*] and [Fe2*] are equal to 0.10 M?
RT
E =E° -.
InQ
nF
Item equation/constant:
F = 96485 J/V mol e and R = 8.314 J/(mol K)
O 0.069 V
O 0.679 V
O 0.658 V
O 0.576 V
amstime](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F120db453-5c07-45ac-b3c7-33c4a8900c95%2F490c3916-d6c6-471a-ad5e-6b55027c73cc%2Fmfe88bj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Consider the reaction at 298 K.
Sn2*(aq) + 2Fe* (aq) Sn4*(aq) + 2FE2*(aq)
E° = 0.617 V
What is the value of E when [Sn2*] and [Fe3*] are equal to 0.50 M and [Sn4*] and [Fe2*] are equal to 0.10 M?
RT
E =E° -.
InQ
nF
Item equation/constant:
F = 96485 J/V mol e and R = 8.314 J/(mol K)
O 0.069 V
O 0.679 V
O 0.658 V
O 0.576 V
amstime
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