Consider the reaction, 2 Al (s) + 6 HCI (aq) → 2 AlCl, (aq) + 3 H, (g). When 40.0 g of Al react with an excess of HCl at 25.0 °C the pressure in a collection flask is measured to be 1.50 atm. What is the volume of the collection flask?

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Consider the reaction, 2 Al (s) + 6 HCI (aq) →
2 AICI, (aq) + 3 H, (g). When 40.0 g of Al react
with an excess of HCl at 25.0 °C the pressure
in a collection flask is measured to be 1.50
atm. What is the volume of the collection
flask?
Transcribed Image Text:Consider the reaction, 2 Al (s) + 6 HCI (aq) → 2 AICI, (aq) + 3 H, (g). When 40.0 g of Al react with an excess of HCl at 25.0 °C the pressure in a collection flask is measured to be 1.50 atm. What is the volume of the collection flask?
Expert Solution
Step 1

Limiting reagent is the reagent which is consumed in the chemical reaction completely. It decides the amount of formation of desired product.

Identification of limiting reagent can be done by the calculation of number of moles of reactants. Divide the value of moles with the stoichiometric coefficients from balanced equation. The least value gives the limiting reagent.

Step 2

In the given reaction, 2 mol of solid Al reacts with 6 mol of aqueous HCl solution to form 2 mol of aqueous solution of AlCl3and 3 mol of H2 gas. 

Since the amount of HCl is in excess, so Al is the limiting reagent.

Mass of Al is 40 g.

Molar mass of Al is 27 g/mol.

Calculate the number of moles of Al.

n of Al=40 g27 g/mol=1.48 mol

Therefore, number of moles of Al is 1.48 mol.

Calculate the number of moles of hydrogen gas to form Al.

n of H2=3 mol2 mol×1.48 mol=2.22 mol

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