Consider the quadratic function f(x) = Ax2 + Bx +C, where A, B, and C are real numbers with A#0. Show that when the Mean Value Theorem is applied to f on the interval [a,b], the number c guaranteed by the theorem is the midpoint of the interval. .... f(b) - f(a) Apply the Mean Value Theorem to f(x) on [a,b]. First, find b-a D/21 f(b) - f(a) 9/21 b-a 3% (5 mited ect yo

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Title: Applying the Mean Value Theorem to Quadratic Functions**

**Course Information:**
- 2021 Fall CRN 45556 Math 2413-10 Remote 10-1140

**Homework Assignment: 4.2**
- Question 4, Part 1 of 4
- HW Score: 83.33%, 5 of 6 points
- Points: 0 of 1

**Student Name:**
- Zeltzin Soriano
- Date: 10/29/21 2:00 PM

**Problem Description:**
Consider the quadratic function \( f(x) = Ax^2 + Bx + C \), where \( A \), \( B \), and \( C \) are real numbers, and \( A \neq 0 \). Show that when the Mean Value Theorem is applied to \( f \) on the interval \([a, b]\), the number \( c \) guaranteed by the theorem is the midpoint of the interval.

**Instructions:**
Apply the Mean Value Theorem to \( f(x) \) on \([a, b]\). First, find 

\[
\frac{f(b) - f(a)}{b-a}
\]

**Solution Space:**
A box is provided to enter the solution for 

\[
\frac{f(b) - f(a)}{b-a}
\] 

Complete this problem using the definition of the Mean Value Theorem and demonstrate the result that the value of \( c \) is the midpoint of \([a, b]\).
Transcribed Image Text:**Title: Applying the Mean Value Theorem to Quadratic Functions** **Course Information:** - 2021 Fall CRN 45556 Math 2413-10 Remote 10-1140 **Homework Assignment: 4.2** - Question 4, Part 1 of 4 - HW Score: 83.33%, 5 of 6 points - Points: 0 of 1 **Student Name:** - Zeltzin Soriano - Date: 10/29/21 2:00 PM **Problem Description:** Consider the quadratic function \( f(x) = Ax^2 + Bx + C \), where \( A \), \( B \), and \( C \) are real numbers, and \( A \neq 0 \). Show that when the Mean Value Theorem is applied to \( f \) on the interval \([a, b]\), the number \( c \) guaranteed by the theorem is the midpoint of the interval. **Instructions:** Apply the Mean Value Theorem to \( f(x) \) on \([a, b]\). First, find \[ \frac{f(b) - f(a)}{b-a} \] **Solution Space:** A box is provided to enter the solution for \[ \frac{f(b) - f(a)}{b-a} \] Complete this problem using the definition of the Mean Value Theorem and demonstrate the result that the value of \( c \) is the midpoint of \([a, b]\).
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