Consider the problem of computing the Riemann-Stieltjes integral S a(x) = x¹/5 We will use the notation from the lectures/notes in the parts below. All answers can be input as calculator-ready expressions, or as decimals. If using the latter, make sure your answer is accurate to at least 4 decimal places. f da for the functions f (x) = 2 - 3x² and a) The interval [4, 7] is to be split into a partition consisting of 16 subintervals [xj-1, xj], j = 1,..., 16 with the a following a geometric sequence. So xo = 4, 16 = 7 and x; r> 1. raj-1 for j = 1, ..., 16 for a suitable choice of For such a partition 8

Advanced Engineering Mathematics
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Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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A and b please
.7
T f da for the functions f (x) = 2 - 3x² and
Consider the problem of computing the Riemann-Stieltjes integral
a(x) = x¹/5
We will use the notation from the lectures/notes in the parts below.
All answers can be input as calculator-ready expressions, or as decimals. If using the latter, make sure your answer
is accurate to at least 4 decimal places.
a)
The interval [4, 7] is to be split into a partition consisting of 16 subintervals [xj-1, xj], j = 1, ..., 16 with the Xj
following a geometric sequence. So xo = 4, 16 = 7 and xj = rxj-1 for j = 1,..., 16 for a suitable choice of
r> 1.
For such a partition 8
Cubrif
Transcribed Image Text:.7 T f da for the functions f (x) = 2 - 3x² and Consider the problem of computing the Riemann-Stieltjes integral a(x) = x¹/5 We will use the notation from the lectures/notes in the parts below. All answers can be input as calculator-ready expressions, or as decimals. If using the latter, make sure your answer is accurate to at least 4 decimal places. a) The interval [4, 7] is to be split into a partition consisting of 16 subintervals [xj-1, xj], j = 1, ..., 16 with the Xj following a geometric sequence. So xo = 4, 16 = 7 and xj = rxj-1 for j = 1,..., 16 for a suitable choice of r> 1. For such a partition 8 Cubrif
b)
The change in a in subinterval 4 is Aα4
The values of the largest and smallest values of f on this subinterval are:
and M4
m4
=
Transcribed Image Text:b) The change in a in subinterval 4 is Aα4 The values of the largest and smallest values of f on this subinterval are: and M4 m4 =
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