Attached is image of the question. Make sure to answer all parts of the question correctly. **Consider the prefix 169.220.2.0/28 and answer the following questions. Show your work.****Question 1:** Write down the mask in dotted decimal notation.**Question 2:** Identify the network address of this prefix.**Question 3:** Identify the broadcast address of this prefix.**Question 4:** How many host addresses are in this prefix?**Question 5:** How many IP addresses in total are in this prefix?

The network's communication structure is determined by the IP address. Subnetting is a technique that divides an IP network into sub-networks for better efficiency and control and involves the use of subnet masks to differentiate between the network and host parts of an IP network.Q1) We can use the subnet mask formula to convert the prefix length (/ 28) into dotted decimal notation. The subnet mask is a 32-bit binary number, where the leftmost consecutive 1s in the subnet mask indicate the network portion and the rightmost consecutive 0s indicate the host portion. With a prefix length of / 28, we have The bits in the network portion : 28 bits (all 1s)Host portion : 32-28 = 4 bits (all 0s)The subnet mask in binary : 11111111.11111111.11111111.11110000Converting the binary mask into dotted decimal notation 255.255.255.240Therefore, the subnet mask in dotted decimal notation is 255.255.255.240.Q2) We must perform a bitwise logical AND operation between the IP address and the subnet mask in order to get the network address of the prefix.IP address : 169.220.2.0Subnet mask : 255.255.255.240Converting both IP and subnet mask into binary representation :IP address :10101001.11011100.00000010.00000000Subnet mask : 11111111.11111111.11111111.11110000Performing bitwise AND operation 10101001.11011100.00000010.00000000AND 11111111.11111111.11111111.11110000------------------------------------------------------- 10101001.11011100.00000010.00000000Converting this binary network address to dotted decimal notation: 169.220.2.0Therefore, the network address the prefix is 169.220.2.0Q3) We need to invert the host part of the subnet mask and use a bitwise OR operation with the network address in order to get the broadcast address of the prefix.The inverted subnet mask for the host part is : 00000000.00000000.00000000.00001111Performing bitwise OR operation 10101001.11011100.00000010.00000000OR 00000000.00000000.00000000.00001111---------------------------------------------------- 10101001.11011100.00000010.00001111Convert this binary broadcast address to dotted decimal notation: 169.220.2.15Therefore, the broadcast address of the prefix is 169.220.2.15.Q4) Since we have 4 bits available for hosts, the total possible addresses are 2^4=16, but two addresses are set aside for the network and broadcast addresses. Therefore, there are 16-2=14 usable host addresses in the prefix.Q5) The total number of IP addresses in the prefix is equal to the number of usable host addresses plus 2.Therefore, 14+2 =16 IP addresses in total in this prefix.Q1) Mask in dotted decimal notation: 255.255.255.240Q2) Network address : 169.220.2.0Q3) Broadcast address : 169.220.2.15Q4) Host addresses in prefix : 14Q5) Total IP addresses in prefix : 16