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Consider the power system shown in Fig. 1. Use a power base of 500 MVA to calculate for a sustained three-phase fault at bus A: (a) The fault current in Amperes. (b) The voltage at bus B during fault. G₁:500 MVA, 13.8 kv, xq=0.2 p.u. G₂:600 MVA, 26 kv, x = 0.15 p.u. G3: 400 MVA, 13.8 kv, x=0.2 p.u. T₁:500 MVA, 13.8 kv/500 kv, x = 0.1 p.u. T₂:600 MVA, 26 kv/500 kv, x=0.1 p.u. T3:500 MVA, 13.8 kv/500 kv, x=0.1 p.u. Line AB, X=800 Line Bc, x=80 2 Line Ω 120 AD, X = Line Dc, x= 100 2

Consider the power system shown in Fig. 1. Use a power base of 500 MVA to calculate for a sustained three-phase fault at bus A: (a) The fault current in Amperes. (b) The voltage at bus B during fault. G₁:500 MVA, 13.8 kv, xq=0.2 p.u. G₂:600 MVA, 26 kv, x = 0.15 p.u. G3: 400 MVA, 13.8 kv, x=0.2 p.u. T₁:500 MVA, 13.8 kv/500 kv, x = 0.1 p.u. T₂:600 MVA, 26 kv/500 kv, x=0.1 p.u. T3:500 MVA, 13.8 kv/500 kv, x=0.1 p.u. Line AB, X=800 Line Bc, x=80 2 Line Ω 120 AD, X = Line Dc, x= 100 2

Power System Analysis and Design (MindTap Course List)
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter2: Fundamentals
Section: Chapter Questions
Problem 2.31P: Consider two interconnected voltage sources connected by a line of impedance Z=jX, as shown in...
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Consider the power system shown in Fig. 1. Use a power base of 500 MVA to calculate for a sustained three-phase fault at bus A: (a) The fault current in Amperes. (b) The voltage at bus B during fault. G₁:500 MVA, 13.8 kv, xq=0.2 p.u. W G₂:600 MVA, 26 kv, x = 0.15 p.u. 11 G3:400 MVA, 13.8 kv, xq = 0.2 p.u. T₁:500 MVA, 13.8 kv/500 kv, x= 0.1 p.u. T₂:600 MVA, 26 kv/500 kv, x=0.1 p.u. T3:500 MVA, 13.8 kv/500 kv, x=0.1 p.u. Line AB, X=8092 , x = 80 Ω Line BC Ω 120 Line AD, X = Line Dc, x= 100 2 T₁ G₁ OBER 30 A B G₂ D 10000 MVA short circuit capacity T3 ) G3 BHO
Transcribed Image Text:Consider the power system shown in Fig. 1. Use a power base of 500 MVA to calculate for a sustained three-phase fault at bus A: (a) The fault current in Amperes. (b) The voltage at bus B during fault. G₁:500 MVA, 13.8 kv, xq=0.2 p.u. W G₂:600 MVA, 26 kv, x = 0.15 p.u. 11 G3:400 MVA, 13.8 kv, xq = 0.2 p.u. T₁:500 MVA, 13.8 kv/500 kv, x= 0.1 p.u. T₂:600 MVA, 26 kv/500 kv, x=0.1 p.u. T3:500 MVA, 13.8 kv/500 kv, x=0.1 p.u. Line AB, X=8092 , x = 80 Ω Line BC Ω 120 Line AD, X = Line Dc, x= 100 2 T₁ G₁ OBER 30 A B G₂ D 10000 MVA short circuit capacity T3 ) G3 BHO
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