Please help me Consider the power system shown in Fig. 1. Use a power base of 500 MVA to calculate for asustained three-phase fault at bus A:(a) The fault current in Amperes.(b) The voltage at bus B during fault.G₁:500 MVA, 13.8 kv, xq=0.2 p.u.WG₂:600 MVA, 26 kv, x = 0.15 p.u.11G3:400 MVA, 13.8 kv, xq = 0.2 p.u.T₁:500 MVA, 13.8 kv/500 kv, x= 0.1 p.u.T₂:600 MVA, 26 kv/500 kv, x=0.1 p.u.T3:500 MVA, 13.8 kv/500 kv, x=0.1 p.u.Line AB, X=8092, x = 80 ΩLine BCΩ 120LineAD, X =Line Dc, x= 100 2T₁G₁OBER30 ABG₂D10000 MVA short circuitcapacityT3) G3BHO

Given base MVA =MVA new =500 MVA Base kV will be not be same for all devices.

Consider the power system shown in Fig. 1. Use a power base of 500 MVA to calculate for a sustained three-phase fault at bus A: (a) The fault current in Amperes. (b) The voltage at bus B during fault. G₁:500 MVA, 13.8 kv, xq=0.2 p.u. G₂:600 MVA, 26 kv, x = 0.15 p.u. G3: 400 MVA, 13.8 kv, x=0.2 p.u. T₁:500 MVA, 13.8 kv/500 kv, x = 0.1 p.u. T₂:600 MVA, 26 kv/500 kv, x=0.1 p.u. T3:500 MVA, 13.8 kv/500 kv, x=0.1 p.u. Line AB, X=800 Line Bc, x=80 2 Line Ω 120 AD, X = Line Dc, x= 100 2

Consider the power system shown in Fig. 1. Use a power base of 500 MVA to calculate for a sustained three-phase fault at bus A: (a) The fault current in Amperes. (b) The voltage at bus B during fault. G₁:500 MVA, 13.8 kv, xq=0.2 p.u. G₂:600 MVA, 26 kv, x = 0.15 p.u. G3: 400 MVA, 13.8 kv, x=0.2 p.u. T₁:500 MVA, 13.8 kv/500 kv, x = 0.1 p.u. T₂:600 MVA, 26 kv/500 kv, x=0.1 p.u. T3:500 MVA, 13.8 kv/500 kv, x=0.1 p.u. Line AB, X=800 Line Bc, x=80 2 Line Ω 120 AD, X = Line Dc, x= 100 2

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter11: Transient Stability

Section: Chapter Questions

Problem 11.19P

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Question

Please help me

Consider the power system shown in Fig. 1. Use a power base of 500 MVA to calculate for a
sustained three-phase fault at bus A:
(a) The fault current in Amperes.
(b) The voltage at bus B during fault.
G₁:500 MVA, 13.8 kv, xq=0.2 p.u.
W
G₂:600 MVA, 26 kv, x = 0.15 p.u.
11
G3:400 MVA, 13.8 kv, xq = 0.2 p.u.
T₁:500 MVA, 13.8 kv/500 kv, x= 0.1 p.u.
T₂:600 MVA, 26 kv/500 kv, x=0.1 p.u.
T3:500 MVA, 13.8 kv/500 kv, x=0.1 p.u.
Line AB, X=8092
, x = 80 Ω
Line BC
Ω 120
Line
AD, X =
Line Dc, x= 100 2
T₁
G₁
OBER
30 A
B
G₂
D
10000 MVA short circuit
capacity
T3
) G3
BHO

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