Please help me Consider the power system shown in Fig. 1. Use a power base of 500 MVA to calculate for asustained three-phase fault at bus A:(a) The fault current in Amperes.(b) The voltage at bus B during fault.G₁:500 MVA, 13.8 kv, xq=0.2 p.u.WG₂:600 MVA, 26 kv, x = 0.15 p.u.11G3:400 MVA, 13.8 kv, xq = 0.2 p.u.T₁:500 MVA, 13.8 kv/500 kv, x= 0.1 p.u.T₂:600 MVA, 26 kv/500 kv, x=0.1 p.u.T3:500 MVA, 13.8 kv/500 kv, x=0.1 p.u.Line AB, X=8092, x = 80 ΩLine BCΩ 120LineAD, X =Line Dc, x= 100 2T₁G₁OBER30 ABG₂D10000 MVA short circuitcapacityT3) G3BHO

Given base MVA =MVA new =500 MVA Base kV will be not be same for all devices.

Consider the power system shown in Fig. 1. Use a power base of 500 MVA to calculate for a sustained three-phase fault at bus A: (a) The fault current in Amperes. (b) The voltage at bus B during fault. G₁:500 MVA, 13.8 kv, xq=0.2 p.u. G₂:600 MVA, 26 kv, x = 0.15 p.u. G3: 400 MVA, 13.8 kv, x=0.2 p.u. T₁:500 MVA, 13.8 kv/500 kv, x = 0.1 p.u. T₂:600 MVA, 26 kv/500 kv, x=0.1 p.u. T3:500 MVA, 13.8 kv/500 kv, x=0.1 p.u. Line AB, X=800 Line Bc, x=80 2 Line Ω 120 AD, X = Line Dc, x= 100 2

Consider the power system shown in Fig. 1. Use a power base of 500 MVA to calculate for a sustained three-phase fault at bus A: (a) The fault current in Amperes. (b) The voltage at bus B during fault. G₁:500 MVA, 13.8 kv, xq=0.2 p.u. G₂:600 MVA, 26 kv, x = 0.15 p.u. G3: 400 MVA, 13.8 kv, x=0.2 p.u. T₁:500 MVA, 13.8 kv/500 kv, x = 0.1 p.u. T₂:600 MVA, 26 kv/500 kv, x=0.1 p.u. T3:500 MVA, 13.8 kv/500 kv, x=0.1 p.u. Line AB, X=800 Line Bc, x=80 2 Line Ω 120 AD, X = Line Dc, x= 100 2

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter11: Transient Stability

Section: Chapter Questions

Problem 11.19P

See similar textbooks

Related questions

Q: What is done to prevent a plan from becoming confusing because of too much details

A: It is the regular exercise that contains the detailed written specifications provided by the…

Q: What type of terminal seal is shown here?

A: Given: What type of terminal seal is shown in figure?

Q: Number 23 please.

Q: Find the difference. 11010011two − 1011101two _____two

A: The result of the difference is, 11010011- 1011101 01110110

Q: 1. What is a bridge circuit?

A: “Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: 16 awg and 18 awg wires that are part of a light fixture, and that are terminated into a ceiling…

A: 16 awg and 18 awg wires that are part of a light fixture, and that are terminated into a ceiling…

Q: Explain what this matching box is. Describe the parts

A: The given diagrams are shown below. It is asked what is this matching box and also it asked to…

Q: Include information about double kelvin bridge in terms of (diagram, construction, work principle,…

A: KELVIN DOUBLE BRIDGE The bridge is called kelvin double bridge because it incorporates the second…

Concept explainers

Electrical Heating Unit

The conversion of electrical energy to heat energy is known as electric heating. The heating system that converts the electrical energy to heat energy for various application is called electrical heating unit. Electricity is employed as the firing mechanism in electric heating systems, which transforms electric current to heat. Electric heaters have heating elements in the form of electric resistors.

Question

Please help me

Consider the power system shown in Fig. 1. Use a power base of 500 MVA to calculate for a
sustained three-phase fault at bus A:
(a) The fault current in Amperes.
(b) The voltage at bus B during fault.
G₁:500 MVA, 13.8 kv, xq=0.2 p.u.
W
G₂:600 MVA, 26 kv, x = 0.15 p.u.
11
G3:400 MVA, 13.8 kv, xq = 0.2 p.u.
T₁:500 MVA, 13.8 kv/500 kv, x= 0.1 p.u.
T₂:600 MVA, 26 kv/500 kv, x=0.1 p.u.
T3:500 MVA, 13.8 kv/500 kv, x=0.1 p.u.
Line AB, X=8092
, x = 80 Ω
Line BC
Ω 120
Line
AD, X =
Line Dc, x= 100 2
T₁
G₁
OBER
30 A
B
G₂
D
10000 MVA short circuit
capacity
T3
) G3
BHO

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Step by step

Solved in 4 steps with 10 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.

Similar questions

Answer all or skip the question
A single-phase, 120V(rms),60Hz source supplies power to a series R-L circuit consisting of R=10 and L=40mH. (a) Determine the power factor of the circuit and state whether it is lagging or leading. (b) Determine the real and reactive power absorbed by the load. (c) Calculate the peak magnetic energy Wint stored in the inductor by using the expression Wint=L(Irms)2 and check whether the reactive power Q=Wint is satisfied. (Note: The instantaneous magnetic energy storage fluctuates between zero and the peak energy. This energy must be sent twice each cycle to the load from the source by means of reactive power flows.)
The subject is: Smart Grid Applications and Technologies Q2
electrical engineering department plzz solve
A non-sinusoidal quasi-square wave voltage v(t) is applied to a nonlinear load, resulting in a non-sinusoidal current i(t). The voltage and current waveforms are shown below. Assume any values of your choice for Vp (≤ 200 V) and Ip (≥ 5 A). 1. calculate the average power and net power factor of the load. 2. The total load harmonic distrotion (THD) of the load current, assuming the smallest frquency term as fundamental.
A 100-MVA synchronous generator supplies 62.5 MVA of power at 0.8 lagging power factor. The reactance between the load and the generator is normally 1.0 pu, but it increases to 3.0 pu because of a sudden three-phase short circuit. The fault is subsequently cleared and the generator then supplies 43.75 MVA at 0.8 lagging power factor. Determine the critical clearing angle. Select one: a. 88.58 b. None c. 78.58 d 68.58
Problem 3 A climate control system, a motor load, and a lightning circuit of a small warehouse establish a 20- kVA power demand at 0.587 power factor lagging on a 240 V, 60 Hz supply. a) Establish the power triangle for the load. b) Determine the power-factor capacitor that must be placed in parallel with the load to raise the power factor to 0.865 lagging. c) Determine the change in supply current from the uncompensated to the compensated system. Explain.
Consider the switching waveforms shown below, operating with a duty-cycle of 30%. Which statements correctly describe the switching circuit, load and circuit operation? (Multiple answers possible, but wrong answers will deduct marks) Voltage across load Voltage (V) 000 120 0000 100 80 60 40 20 30 Time (us) The load must be predominantly resistive. The average current in the load is 1.0A. The RMS current in the load is approximately 1.414A. The load must be predominantly inductive. The resistive part of the load is 200ohms. The average current in the load is 0.6A. O The resistive part of the load is 50ohms. 0 0 10 20 40 50 60 Current (A) 2 5 0.5 0 0 10 Current through load 20 W 30 Time (us) 40 50 60
The peak load on a 50 MW power station is 39 MW. It supplies power through for transformers whose connected loads are 17, 12,9 and 10 MW. The maximum demands on these transformers are 15, 10, 8 and 9 MW respectively. The annual load factor is 50% and the plant is operating for 65% of the period in a year. 102. The average load on the station is (A) 50000 kW (C) 39000 kW (B) 19500 kW (D) 48000 kW. 103. The energy supplied per year is (A) 438 x 106 kWh (C) 170.82 x 106 kWh (B) 341.64 x 106 kWh (D) 420.48 x 106 kWh.
The following data relate to a 50 Hz generator. e.m.f. to neutral = 7.5 kV (rms) Reactance of generator and connected system = 5Ω Distributed capacitance to neutral = 0.02 µF (Resistance negligible) Calculate the following: (1) Maximum voltage across the contacts of circuit breaker when it breaks a short circuit current at zero current. (2) Frequency of the transient oscillation.
The circuit shows an unbalanced electrical installation powered by a positive sequence symmetrical three-phase network of 380 V compound voltage. The loads are single phase. Load 1 absorbs an active power of 950 W with f.d.p. 0.5 inductive. Load 2 absorbs an active power of 1,140 W with f.d.p. Unit. Load 3 absorbs from the network an active power of 760 W with f.d.p. 0.5 capacitive. Taking the network voltage URN as the phase reference, calculate: a) complex expressions of the line currents IR. Is. and IT
A 60 Hz, 33 kV, 3-phase alternator with earthed neutral has a reactance of 7 ohms per phase and is connected to a bus-bar through a circuit breaker. The distributed capacitance upto circuit breaker between phase and neutral in 0.03 uF. Determine (i) peak re-striking voltage across the contacts of the breaker (ii) frequency of oscillations