Consider the pair of reactions. Draw the organic products, then predict the type of substitution mechanism and compare the expected rates.

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**Organic Chemistry: Substitution Reactions**

**Presented by Macmillan Learning**

**Consider the pair of reactions. Draw the organic products, then predict the type of substitution mechanism and compare the expected rates.**

### Reaction 1:
- **Reactants:** 
  - 1-chlorobutane (\( \text{Cl}\) connected to a butane chain)
  - \( \text{Br}^-\) (bromide ion)
- **Solvent:** DMF (Dimethylformamide)
- **Product:** Product 1 (to be drawn)

### Reaction 2:
- **Reactants:**
  - 1-chlorobutane (\( \text{Cl}\) connected to a butane chain)
  - \( \text{I}^-\) (iodide ion)
- **Solvent:** DMF (Dimethylformamide)
- **Product:** Product 2 (to be drawn)

### Drawing Area:
- Two interactive drawing sections for products:
  - Draw product 1 (includes tools for lines, rings, carbon, hydrogen, and bromine).
  - Draw product 2 (includes tools for lines, rings, carbon, hydrogen, and iodine).

### Identify the Mechanism of Each Reaction:
- [ ] Reaction 1 occurs by an \( S_N1 \) mechanism.
- [x] Reaction 1 occurs by an \( S_N2 \) mechanism.
- [ ] Reaction 2 occurs by an \( S_N1 \) mechanism.
- [x] Reaction 2 occurs by an \( S_N2 \) mechanism.

### Compare the Rates of Each Reaction:
- [ ] Reaction 1 is faster than reaction 2.
- [ ] Both reactions occur at the same rate.
- [x] Reaction 2 is faster than reaction 1.

--- 

**Explanation:**

In these reactions, 1-chlorobutane undergoes substitution with bromide and iodide ions in an \( S_N2 \) mechanism, which is favored because the leaving group is primary. Iodide is a better nucleophile than bromide, so Reaction 2 is expected to be faster than Reaction 1.
Transcribed Image Text:**Organic Chemistry: Substitution Reactions** **Presented by Macmillan Learning** **Consider the pair of reactions. Draw the organic products, then predict the type of substitution mechanism and compare the expected rates.** ### Reaction 1: - **Reactants:** - 1-chlorobutane (\( \text{Cl}\) connected to a butane chain) - \( \text{Br}^-\) (bromide ion) - **Solvent:** DMF (Dimethylformamide) - **Product:** Product 1 (to be drawn) ### Reaction 2: - **Reactants:** - 1-chlorobutane (\( \text{Cl}\) connected to a butane chain) - \( \text{I}^-\) (iodide ion) - **Solvent:** DMF (Dimethylformamide) - **Product:** Product 2 (to be drawn) ### Drawing Area: - Two interactive drawing sections for products: - Draw product 1 (includes tools for lines, rings, carbon, hydrogen, and bromine). - Draw product 2 (includes tools for lines, rings, carbon, hydrogen, and iodine). ### Identify the Mechanism of Each Reaction: - [ ] Reaction 1 occurs by an \( S_N1 \) mechanism. - [x] Reaction 1 occurs by an \( S_N2 \) mechanism. - [ ] Reaction 2 occurs by an \( S_N1 \) mechanism. - [x] Reaction 2 occurs by an \( S_N2 \) mechanism. ### Compare the Rates of Each Reaction: - [ ] Reaction 1 is faster than reaction 2. - [ ] Both reactions occur at the same rate. - [x] Reaction 2 is faster than reaction 1. --- **Explanation:** In these reactions, 1-chlorobutane undergoes substitution with bromide and iodide ions in an \( S_N2 \) mechanism, which is favored because the leaving group is primary. Iodide is a better nucleophile than bromide, so Reaction 2 is expected to be faster than Reaction 1.
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