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Consider the ordinary differential equation y"(x) = 4y(x) + 4, y(0)=y'(0) = 1, (d) which is second order (because of the second derivative), not first order. So we may not directly employ our methods. However, let z(x) be the function given by z(x) = y'(x) + 2y(x). (z) 6.a Assuming y(x) is a solution to (d), determine a differential equation for z(x) (involving z(x) and z'(x) (0)

Consider the ordinary differential equation y"(x) = 4y(x) + 4, y(0)=y'(0) = 1, (d) which is second order (because of the second derivative), not first order. So we may not directly employ our methods. However, let z(x) be the function given by z(x) = y'(x) + 2y(x). (z) 6.a Assuming y(x) is a solution to (d), determine a differential equation for z(x) (involving z(x) and z'(x) (0)

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Consider the ordinary differential equation y"(x) = 4y(x) +4, y(0)= y′(0) = 1, (d) which is second order (because of the second derivative), not first order. So we may not directly employ our methods. However, let z(x) be the function given by z(x) = y'(x) + 2y(x). (z) 6.a Assuming y(x) is a solution to (d), determine a differential equation for z(x) (involving z(x) and z'(x) but not y(x) or its derivatives) as well as its initial value z(0). Hint: First compute z'(x) in terms of the derivatives y"(x) and y'(x). Then use (d) to re-express y'(x). 6.b Solve for z(x) in the previous problem. 6.c Use your solution for z(x) to solve for y(x) by solving (z) for y with initial condition y(0) = 1.
Transcribed Image Text:Consider the ordinary differential equation y"(x) = 4y(x) +4, y(0)= y′(0) = 1, (d) which is second order (because of the second derivative), not first order. So we may not directly employ our methods. However, let z(x) be the function given by z(x) = y'(x) + 2y(x). (z) 6.a Assuming y(x) is a solution to (d), determine a differential equation for z(x) (involving z(x) and z'(x) but not y(x) or its derivatives) as well as its initial value z(0). Hint: First compute z'(x) in terms of the derivatives y"(x) and y'(x). Then use (d) to re-express y'(x). 6.b Solve for z(x) in the previous problem. 6.c Use your solution for z(x) to solve for y(x) by solving (z) for y with initial condition y(0) = 1.
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