Consider the mechanical energy of a body in geostationary orbit above the Earth's equator, at rGs = 42000 km. Consider the mechanical energy of the same body on Earth at the South pole, at re = 6400 km. For this problem, we consider the Earth to be spherical. (Remember, the object at the equator traces a circular path, the object at the Pole does not.) G = 6.67 x 10-11 Nm?kg2, and the mass of the Earth is M = 5.97 x 1024 kg All else equal, should you put your launch sites at a low or high latitude? (Low latitudes being closer to the Equator, high latitudes being closer to the Poles.) Low latitudes High latitudes O It makes no difference
Consider the mechanical energy of a body in geostationary orbit above the Earth's equator, at rGs = 42000 km. Consider the mechanical energy of the same body on Earth at the South pole, at re = 6400 km. For this problem, we consider the Earth to be spherical. (Remember, the object at the equator traces a circular path, the object at the Pole does not.) G = 6.67 x 10-11 Nm?kg2, and the mass of the Earth is M = 5.97 x 1024 kg All else equal, should you put your launch sites at a low or high latitude? (Low latitudes being closer to the Equator, high latitudes being closer to the Poles.) Low latitudes High latitudes O It makes no difference
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![10. [#8510] Energy per kilo (Part 3)
Consider the mechanical energy of a body in geostationary orbit above the Earth's equator, at rGs = 42000 km.
Consider the mechanical energy of the same body on Earth at the South pole, at re = 6400 km. For this problem, we consider the Earth to be spherical.
(Remember, the object at the equator traces a circular path, the object at the Pole does not.)
G = 6.67 x 10-11 Nm²kg?, and the mass of the Earth is M = 5.97 x 1024 kg
All else equal, should you put your launch sites at a low or high latitude?
(Low latitudes being closer to the Equator, high latitudes being closer to the Poles.)
O Low latitudes
O High latitudes
It makes no difference](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa8308f50-2679-45b8-9394-7556035d4571%2F14f34d14-fe87-4b0f-b6f0-ea233dfd3f23%2Flck9kmc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:10. [#8510] Energy per kilo (Part 3)
Consider the mechanical energy of a body in geostationary orbit above the Earth's equator, at rGs = 42000 km.
Consider the mechanical energy of the same body on Earth at the South pole, at re = 6400 km. For this problem, we consider the Earth to be spherical.
(Remember, the object at the equator traces a circular path, the object at the Pole does not.)
G = 6.67 x 10-11 Nm²kg?, and the mass of the Earth is M = 5.97 x 1024 kg
All else equal, should you put your launch sites at a low or high latitude?
(Low latitudes being closer to the Equator, high latitudes being closer to the Poles.)
O Low latitudes
O High latitudes
It makes no difference
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