Consider the matrices A = | 1 U = 1 0 a b b [f] g V = h a 1³-1 d, B = 0 C f 1 d g 1 C h a² X 0 and X = y. If AX = U has infinitely A 0 Z many solutions, then prove that BX= V has no unique solution. Also, show that if afd # 0, then BX = V has no solution.

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Q: Q3: if it was V2 B =1.A = [VZ o 3] 1.A [V2 O 3) Find В.А A.B , VZB

A: 3B=21-2 ,  A=203B.A=21-23*1 , A= 2031*3=222023121013-22-20-23=2032203-220-6

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A: to find the row reduced echelon form of -4       31      - 1-3       42       - 23        2

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Q: For which value of x is the following matrix not invertible: 1 1 2x A = 1 2x 2x 2x 2x 2x 4 1 -1 1 2

A: For a matrix A to not be invertible: dat(A) = 0.

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Q: [1 3 B = 2 1 5 0 A = 0 -5 4 and 3 8 QA + B'.

A: