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Consider the LTI system with the following block diagram. R(s) 1 Y(s) s2 +1 (a) Find the unit step response of the closed-loop system. (b) Find the steady-state error (i.e., e(t) = r(t) – y(t)) to the unit-step reference input.

Consider the LTI system with the following block diagram. R(s) 1 Y(s) s2 +1 (a) Find the unit step response of the closed-loop system. (b) Find the steady-state error (i.e., e(t) = r(t) – y(t)) to the unit-step reference input.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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EECE 4000 February 24, 2021 No Credit will be given unless showing details. 1. Consider the LTI system with the following block diagram. 1 Y (s) R(s) s2 +1 (a) Find the unit step response of the closed-loop system. (b) Find the steady-state error (i.e., e(t) = r(t) – y(t)) to the unit-step reference input. ** With zero initial conditions, the unit-step response of a LTI system is = e-3t+12u(t - 4) + u(t- 4) where u(t)
Transcribed Image Text:EECE 4000 February 24, 2021 No Credit will be given unless showing details. 1. Consider the LTI system with the following block diagram. 1 Y (s) R(s) s2 +1 (a) Find the unit step response of the closed-loop system. (b) Find the steady-state error (i.e., e(t) = r(t) – y(t)) to the unit-step reference input. ** With zero initial conditions, the unit-step response of a LTI system is = e-3t+12u(t - 4) + u(t- 4) where u(t)
Expert Solution
Step 1

As only the first question is complete, and the second question is incomplete, so I am going to answer only the first question.

Unit step response of a system is defined as the output at the input is step signal.

A steady-state error of a signal has been explained in the below solutions.

 

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