Consider the line L(t)=⟨4−t,−4−2t,−5−3t⟩L(t)=⟨4−t,−4−2t,−5−3t⟩. Then:     L is           to the plane 8z−(2x+11y)=−208z−(2x+11y)=−20       L is           to the plane 1.5x+3y+4.5z=−31.5x+3y+4.5z=−3       L is           to the plane 9z−(15x+6y)=−39z−(15x+6y)=−3       L is           to the plane x+5z=−15x+5z=−15   Answer options are Perpendicular Parellel or neither

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Consider the line L(t)=⟨4−t,−4−2t,−5−3t⟩L(t)=⟨4−t,−4−2t,−5−3t⟩. Then:

 

  L is           to the plane 8z−(2x+11y)=−208z−(2x+11y)=−20

 

 
  L is           to the plane 1.5x+3y+4.5z=−31.5x+3y+4.5z=−3

 

 
  L is           to the plane 9z−(15x+6y)=−39z−(15x+6y)=−3

 

 
  L is           to the plane x+5z=−15x+5z=−15

 

Answer options are Perpendicular Parellel or neither

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