Consider the linear system of equations, where k is a constant. erek x + y+ kz = k2 %3D x + ky + z = k kx +y + z = 1 Find the valus(s) of k such that: a) the system has a unique solution. b) the system has more than one solution. c) the system has NO solution.
Consider the linear system of equations, where k is a constant. erek x + y+ kz = k2 %3D x + ky + z = k kx +y + z = 1 Find the valus(s) of k such that: a) the system has a unique solution. b) the system has more than one solution. c) the system has NO solution.
Algebra and Trigonometry (MindTap Course List)
4th Edition
ISBN:9781305071742
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter10: Systems Of Equations And Inequalities
Section10.CR: Chapter Review
Problem 3CC: What is a system of linear equations in the variables x, y, and z?
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Equations and Inequations
Equations and inequalities describe the relationship between two mathematical expressions.
Linear Functions
A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.
Question
![Consider the linear system of equations, where k is a constant.
erek
x + y+ kz = k2
%3D
x + ky + z = k
kx +y + z = 1
Find the valus(s) of k such that:
a) the system has a unique solution.
b) the system has more than one solution.
c) the system has NO solution.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb683cc29-07ef-4ab0-a977-798e14b390cd%2F4b5c0963-e8a7-4b9d-ac89-dd37daab95ec%2Fxgbdhr.jpeg&w=3840&q=75)
Transcribed Image Text:Consider the linear system of equations, where k is a constant.
erek
x + y+ kz = k2
%3D
x + ky + z = k
kx +y + z = 1
Find the valus(s) of k such that:
a) the system has a unique solution.
b) the system has more than one solution.
c) the system has NO solution.
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