Consider the length of the simple pendulum is 1 and the mass of the pendulum bob is m . Obtain the equation for the Lagrangian for the simple pendulum when its kinetic energy is 1 m². &* and the potential energy is mgl(1- cos ø) . 1 (A) –-ml ở – mgl(1–cos ø) 2 1 (B) - ml ở – mgl(1-cos ø) 2 1 (C) –mlo + mgl (1– cos ø) 1 (D) – ml ở – 2mg (1– cos ø) 2

Consider the length of the simple pendulum is 1 and the mass of the pendulum bob is m . Obtain the equation for the Lagrangian for the simple pendulum when its kinetic energy is 1 m². &* and the potential energy is mgl(1- cos ø) . 1 (A) –-ml ở – mgl(1–cos ø) 2 1 (B) - ml ở – mgl(1-cos ø) 2 1 (C) –mlo + mgl (1– cos ø) 1 (D) – ml ở – 2mg (1– cos ø) 2