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Consider the intersection curve C in the first octant, between the surfaces S1: P = (1,1,1) z=1-2² y S₂: y = 2x. Let a point on C, as shown in the figure: 2=1-x² P 2x H x A tangent vector to curve C at P corresponds to: A) = (1,2,-1) B) = (1, 1,-1) C) = (1,2,-2) D) 7 = (1,1,-2) Y

Consider the intersection curve C in the first octant, between the surfaces S1: P = (1,1,1) z=1-2² y S₂: y = 2x. Let a point on C, as shown in the figure: 2=1-x² P 2x H x A tangent vector to curve C at P corresponds to: A) = (1,2,-1) B) = (1, 1,-1) C) = (1,2,-2) D) 7 = (1,1,-2) Y

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Consider the intersection curve C in the first octant, between the surfaces S1: z=1-2² y S₂: y = 2x. P = (1,1,2) Let z=1-2² P A tangent vector to curve C at P corresponds to: A) = (1,2,-1) B) = (1,1,-1) C) = (1,2,-2) D) 7 = (1, 1, -2) a point on C, as shown in the figure: y = 2a Y
Transcribed Image Text:Consider the intersection curve C in the first octant, between the surfaces S1: z=1-2² y S₂: y = 2x. P = (1,1,2) Let z=1-2² P A tangent vector to curve C at P corresponds to: A) = (1,2,-1) B) = (1,1,-1) C) = (1,2,-2) D) 7 = (1, 1, -2) a point on C, as shown in the figure: y = 2a Y
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