Can you help me find parts (a) & (b) of this question? Consider the integral7(4x2 + 2x + 2) dx(a) Find the Riemann sum for this integral using left endpoints and 3 equal subintervals.(b) Find the Riemann sum for this integral, using right endpoints and 3 equal subintervals.

Given: ∫174x2+2x+2dx with n=3 rectangles.Explanation: a) Using Left Endpoints: Reimann sum is also known as the left endpoint approximation, which uses left endpoints of a subinterval: ∫abf(x)dx≈∆xfx0+fx1+...+fxn-1Where ∆x is the width,∆x=b-an.We have that a=0, b=7, n=3Therefore,∆x=b-an=7-03=73Now divide the interval [0,7] into n=3 subinterval of length∆x=73a=0,73 , 73, 143 , 143, 7=bNow we just evaluate the function at the left endpoints:f(x0)=f(a)=f(0)=2f(x1)=f73=2569=28.4444f(x2)=f143=8869=98.4444Finally , just sum up the above values andd multiply by ∆x=73732+28.4444+98.4444=300.7407Therefore,∫074x2+2x+2dx≈300.7407 Using left endpoints the area under the curve is approximately 300.7407b) Using Right Endpoints: Reimann sum is also known as the right endpoint approximation, which uses right endpoints of a subinterval: ∫abf(x)dx≈∆xfx1+fx2...+fxn-1Where ∆x is the width,∆x=b-an.We have that a=0, b=7, n=3Therefore,∆x=b-an=7-03=73Now divide the interval [0,7] into n=3 subinterval of length∆x=73a=0,73 , 73, 143 , 143, 7=bNow we just evaluate the function at the left endpoints:f(x1)=f73=2569=28.4444f(x2)=f143=8869=98.4444f(x3)=fb=f(7)=212Finally , just sum up the above values andd multiply by ∆x=737328.4444+98.4444+212=790.7407Therefore,∫074x2+2x+2dx≈790.7407 Using right endpoints the area under the curve is approximately 300.7407 Hence the solution.