Consider the integral / 3x* (25 + 1) dz. In the following, we will evaluate the integral using two methods. A. First, rewrite the integral by multiplying out the integrand: | 32* (z* + 1) dz =| 3x°9+3x*4 dz Then evaluate the resulting integral term-by-term: | 32 (2* + 1) dz = B. Next, rewrite the integral using the substitution w = 25 +1: | 3z* (z* + 1) dz =|| dw Evaluate this integral (and back-substitute for w) to find the value of the original integral: | 32* (2* + 1) dr =

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