Consider the initial-value problem: {/0 y' - 2y = 4e-2t, y (0) = 6. Use the Laplace transform to find the unique solution for y(t). ylt

Q: æ' + x = 2+ 8(t – 1), x(0) = 0. Find the Laplace transform of the solution. X(s) = L {x(t)} = help…

A:

Q: Use the Laplace transform to solve the given initial-value problem. y' - 2y = 5(t – 4), y(0) = 0…

A: The solution is given as

Q: Use laplace transform to solve the initial value problem; a) y''+9y=cos3t,y(0)=2, y'(0)=5.

A: We shall use Laplace and inverse Laplace transform to solve this

Q: a' +x = 6+ 8(t – 4), x(0) = 0. Find the Laplace transform of the solution. X(s) = L {x(t)} = help…

A:

Q: Use the Laplace transform to solve the given initial-value problem. y' + 5y = et, v(0) = 2 y(t) =

A:

Q: ý + 16y = 8 (t – ) sin (2t), y(0) = 0, ÿ(0) = 0

A: The solution is given by using some formulas of Laplace transform as follows :

Q: Use the Laplace transform to solve the given initial-value problem. y' +2y = e-2t, y(0) = 3 y(t)=

A:

Q: 6. Use the Laplace Transform to solve the initial value problem: y' +9y = e-tcos (2t), y(0) = 0

A: Given that the initial value problem y'+9y=e-tcos2t   , y0=0    .