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Consider the indefinite integral Then the integrand decomposes into the form с d ax + b + where a = b = C = d = f620² 6x³+4x²+1x −1 dx x² - 1 + x 1 x + 1 Integrating term by term, we obtain that 6x³+4x²+1x-1 dx = x² - 1 +C

Consider the indefinite integral Then the integrand decomposes into the form с d ax + b + where a = b = C = d = f620² 6x³+4x²+1x −1 dx x² - 1 + x 1 x + 1 Integrating term by term, we obtain that 6x³+4x²+1x-1 dx = x² - 1 +C

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
Consider the indefinite integral a = Then the integrand decomposes into the form с d ax+b+ where b = C = d = 6x³+4x²+1x - 1 x² - 1 fº + x 1 x + 1 Integrating term by term, we obtain that 6x³+4x²+1x - 1 1² dx = x² - 1 dx +C
Transcribed Image Text:Consider the indefinite integral a = Then the integrand decomposes into the form с d ax+b+ where b = C = d = 6x³+4x²+1x - 1 x² - 1 fº + x 1 x + 1 Integrating term by term, we obtain that 6x³+4x²+1x - 1 1² dx = x² - 1 dx +C
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