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Consider the indefinite integral dz: (e-2= + 2)5 This can be transformed into a basic integral by letting u = -2x + 2 v and e du = -2e-2z v dr Performing the substitution yields the integral x du u? Integrating yields the result 1 +C 4(e-2 + 2)*

Consider the indefinite integral dz: (e-2= + 2)5 This can be transformed into a basic integral by letting u = -2x + 2 v and e du = -2e-2z v dr Performing the substitution yields the integral x du u? Integrating yields the result 1 +C 4(e-2 + 2)*

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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got that 3rd part incorrect, please help

 

2e-22 Consider the indefinite integral dx: (e- 2z + 2)5 This can be transformed into a basic integral by letting u = e-2z +2v and du -2e-2x v d Performing the substitution yields the integral x du Integrating yields the result 1. +C 4(e-24 + 2)*
Transcribed Image Text:2e-22 Consider the indefinite integral dx: (e- 2z + 2)5 This can be transformed into a basic integral by letting u = e-2z +2v and du -2e-2x v d Performing the substitution yields the integral x du Integrating yields the result 1. +C 4(e-24 + 2)*
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