Consider the indefinite integral a (3 + 11a°)" dx. (a) The most appropriate substitution is u = (b) After making the substitution, we obtain the integral du. (c) Solving this integral (in terms of u) yields P +C. (d) Substituting for u we obtain the answer a*(3+112)" de = P +C.

Q: dx 4. x(х + 4) 1

A: Consider the given integration as ∫1∞dxxx+4

Q: tan (? + ?/4) = −√3.

A: tan(? + ?/4) = –√3 To find the value of ? in the equation : tan(? + ?/4) = –√3 we can use the…

Q: dx (1 + x) Vĩ

A: To determine the value of integral.

Q: (Vx – 1)² dx

A:

Q: 10. Given: CH bisects ZDHG , mGF = (2x + 6) , and mDC = (7x – 1)'. E H C G F

A:

Q: Solve ydæ %3D (е9/2 + 20у — 2л)dy - = A- B I . E E E E 8 &

A:

Q: dx (x² +25)3/2

A: To find the integration.

Q: 7. secx dx COS X

A:

Q: T/2 cscmx dx then 5 l6 - 4 4 =.... T/4 If Im %3D Answer:

A: Solve the following

Q: solve for y=3 (Find all solutions)  y = 2+5cos((pi/7)(x+1))

A:

Q: 9x 2 dx ,2

A:

Q: Evaluate S₁ 45 dx 1- cos (9x)

A: To evaluate .

Q: Solve f (cosh 4x + sinh 2x) dx then evaluate the answer at x=-7 and C=33

A:

Q: x² 3 (x + 2)5 S dx

A: ∫un du = un+1n+1+C

Q: x dx in two ways: using the direct substitution u = x² – 4 x? - 4 and by trigonometric 11. Evaluate…

A:

Q: T/4 35 (tan20tan + 1) sec20 d0 0

A: The integral is given by,

Q: sinc(2nBt – mn) sinc(2nBt n7

A:

Q: x+3 dx 1-x2

A: This problem can be solved using the concept of integration by substitution.

Q: сп/2 Cos 2x d.x 11 Jo

A: V

Q: 23 1 dr Evaluate - Express your answers in the form: Axm + Br" + DxP.

A:

Q: Evaluate 1₁-² 63 dx 1- cos (9x) 63 dx 1- cos (9x) - 7 cot 9x 2 +C

A: To evaluate the given integral.

Q: e* dx 3 – 2e* – e 2x

A: To solve the integral given by; ∫ex3-2ex-e2xdx let; ex=t∴exdx=dt Therefore the above integral…

Q: I. Power Formula sec² xdx 1. S (1–4tanx)7 (2x+1)dx (x+2)*(x-1)* 2. S;

A: In this question we have to find the following integral using power formula. We know, Power formula,…

Q: tan(0.2x - π)= -9

A:

Q: x (1+x²) dx

A: Let, I=∫x1+x2dx  ............(1) Substitute, u=x2+1 dudx=2x dx=12xdu Put these values in equation…

Q: tan-1x dx. 1 + x2 Use an appropriate substitution to solve

A:

Q: Steps S 10sin(2x)cos(2x)V cos (2x) – 5 dx

A:

Q: (4 - x*)3/2 dx

A:

Q: 3 |(3 -x).

A: Integration of 3-x w. r. t to x for limit 0 to 3

Q: foro ses3 1 for0 <<8 Solve sin 3x=

A: