Consider the indefinite integral + 222 – 29z – 21 da. 1² – 9 The integrand decomposes into the form ar + b+ 3 z + 3 where a = b = c = d = Integrating term by term, we obtain that (4x³ + 2z2 – 29r – 21 da = 22 – 9 +C.
Consider the indefinite integral + 222 – 29z – 21 da. 1² – 9 The integrand decomposes into the form ar + b+ 3 z + 3 where a = b = c = d = Integrating term by term, we obtain that (4x³ + 2z2 – 29r – 21 da = 22 – 9 +C.
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.3: The Natural Exponential Function
Problem 58E
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Question
![Consider the indefinite integral
(4x3 + 2x2 - 29x – 21
dx.
x2 – 9
The integrand decomposes into the form
d
+
- 3
ах + b +
I + 3
where
a =
b =
c =
d
%3D
Integrating term by term, we obtain that
(4x + 2x2 – 29x – 21
dx =
x2 – 9
+C.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcc7f96b0-6dc0-4972-bfe0-9c219792bf84%2F57023e42-76a1-4523-b34f-e7021fe91c41%2Fs8rl83o_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Consider the indefinite integral
(4x3 + 2x2 - 29x – 21
dx.
x2 – 9
The integrand decomposes into the form
d
+
- 3
ах + b +
I + 3
where
a =
b =
c =
d
%3D
Integrating term by term, we obtain that
(4x + 2x2 – 29x – 21
dx =
x2 – 9
+C.
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