Consider the hypothesis statement to the right. Ho: o 25.0 State your conclusion given that s = 1.6, n= 25, and a = 0.05. H,:o < 5.0 1 Click the icon to view a table of chi-square critical values. Calculate the appropriate test statistic. The test statistic is (Round to two decimal places as needed.) Determine the appropriate critical value(s). The critical value(s) is(are) (Round to three decimal places as needed. Use a comma to separate answers as needed.) (1) the null hypothesis. There is (2) evidence that the population variance is (3) 5.0.

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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100%
(1)
the null hypothesis. There is (2)
evidence that the population variance is (3)
5.0.
1: Table of Chi-square Critical Values
Chi-Square Distribution: Area in Right Tail of Distribution
d.f.
0.995
0.99
0.975
0.95
0.90
0.10
0.05
0.025
0.01
0.005
1
0.001
0.004
0.016
2.706
3.841
5.024
6.635
7.879
-
0.010
0.020
0.051
0.103
0.211
4.605
5.991
7.378
9.210
10.597
3
0.072
0.115
0.216
0.352
0.584
6.251
7.815
9.348
11.345
12.838
4
0.207
0.297
0.484
0.711
1.064
7.779
9.488
11.143
13.277
14.860
5
0.412
0.554
0.831
1.145
1.610
9.236
11.070
12.833
15.086
16.750
6
0.676
0.872
1.237
1.635
2.204
10.645
12.592
14.449
16.812
18.548
7
0.989
1.239
1.690
2.167
2.833
12.017
14.067
16.013
18.475
20.278
8
1.344
1.646
2.180
2.733
3.490
13.362
15.507
17.535
20.090
21.955
9
1.735
2.088
2.700
3.325
4.168
14.684
16.919
19.023
21.666
23.589
10
2.156
2.558
3.247
3.940
4.865
15.987
18.307
20.483
23.209
25.188
11
2.603
3.053
3.816
4.575
5.578
17.275
19.675
21.920
24.725
26.757
12
3.074
3.571
4.404
5.226
6.304
18.549
21.026
23.337
26.217
28.300
13
3.565
4.107
5.009
5.892
7.042
19.812
22.362
24.736
27.688
29.819
14
4.075
4.660
5.629
6.571
7.790
21.064
23.685
26.119
29.141
31.319
15
4.601
5.229
6.262
7.261
8.547
22.307
24.996
27.488
30.578
32.801
16
5.142
5.812
6.908
7.962
9.312
23.542
26.296
28.845
32.000
34.267
17
5.697
6.408
7.564
8.672
10.085
24.769
27.587
30.191
33.409
35.718
18
6.265
7.015
8.231
9.390
10.865
25.989
28.869
31.526
34.805
37.156
19
6.844
7.633
8.907
10.117
11.651
27.204
30.144
32.852
36.191
38.582
20
7.434
8.260
9.591
10.851
12.443
28.412
31.410
34.170
37.566
39.997
21
8.034
8.897
10.283
11.591
13.240
29.615
32.671
35.479
38.932
41.401
22
8.643
9.542
10.982
12.338
14.041
30.813
33.924
36.781
40.289
42.796
23
9.260
10.196
11.689
13.091
14.848
32.007
35.172
38.076
41.638
44.181
24
9.886
10.856
12.401
13.848
15.659
33.196
36.415
39.364
42.980
45.559
25
10.520
11.524
13.120
14.611
16.473
34.382
37.652
40.646
44.314
46.928
26
11.160
12.198
13.844
15.379
17.292
35.563
38.885
41.923
45.642
48.290
27
11.808
12.879
14.573
16.151
18.114
36.741
40.113
43.195
46.963
49.645
28
12.461
13.565
15.308
16.928
18.939
37.916
41.337
44.461
48.278
50.993
29
13.121
14.256
16.047
17.708
19.768
39.087
42.557
45.722
49.588
52.336
30
13.787
14.953
16.791
18.493
20.599
40.256
43.773
46.979
50.892
53.672
O Reject
O Do not reject
(2) O insufficient
O sufficient
(1)
(3)
O less than
O greater than
different from
Transcribed Image Text:(1) the null hypothesis. There is (2) evidence that the population variance is (3) 5.0. 1: Table of Chi-square Critical Values Chi-Square Distribution: Area in Right Tail of Distribution d.f. 0.995 0.99 0.975 0.95 0.90 0.10 0.05 0.025 0.01 0.005 1 0.001 0.004 0.016 2.706 3.841 5.024 6.635 7.879 - 0.010 0.020 0.051 0.103 0.211 4.605 5.991 7.378 9.210 10.597 3 0.072 0.115 0.216 0.352 0.584 6.251 7.815 9.348 11.345 12.838 4 0.207 0.297 0.484 0.711 1.064 7.779 9.488 11.143 13.277 14.860 5 0.412 0.554 0.831 1.145 1.610 9.236 11.070 12.833 15.086 16.750 6 0.676 0.872 1.237 1.635 2.204 10.645 12.592 14.449 16.812 18.548 7 0.989 1.239 1.690 2.167 2.833 12.017 14.067 16.013 18.475 20.278 8 1.344 1.646 2.180 2.733 3.490 13.362 15.507 17.535 20.090 21.955 9 1.735 2.088 2.700 3.325 4.168 14.684 16.919 19.023 21.666 23.589 10 2.156 2.558 3.247 3.940 4.865 15.987 18.307 20.483 23.209 25.188 11 2.603 3.053 3.816 4.575 5.578 17.275 19.675 21.920 24.725 26.757 12 3.074 3.571 4.404 5.226 6.304 18.549 21.026 23.337 26.217 28.300 13 3.565 4.107 5.009 5.892 7.042 19.812 22.362 24.736 27.688 29.819 14 4.075 4.660 5.629 6.571 7.790 21.064 23.685 26.119 29.141 31.319 15 4.601 5.229 6.262 7.261 8.547 22.307 24.996 27.488 30.578 32.801 16 5.142 5.812 6.908 7.962 9.312 23.542 26.296 28.845 32.000 34.267 17 5.697 6.408 7.564 8.672 10.085 24.769 27.587 30.191 33.409 35.718 18 6.265 7.015 8.231 9.390 10.865 25.989 28.869 31.526 34.805 37.156 19 6.844 7.633 8.907 10.117 11.651 27.204 30.144 32.852 36.191 38.582 20 7.434 8.260 9.591 10.851 12.443 28.412 31.410 34.170 37.566 39.997 21 8.034 8.897 10.283 11.591 13.240 29.615 32.671 35.479 38.932 41.401 22 8.643 9.542 10.982 12.338 14.041 30.813 33.924 36.781 40.289 42.796 23 9.260 10.196 11.689 13.091 14.848 32.007 35.172 38.076 41.638 44.181 24 9.886 10.856 12.401 13.848 15.659 33.196 36.415 39.364 42.980 45.559 25 10.520 11.524 13.120 14.611 16.473 34.382 37.652 40.646 44.314 46.928 26 11.160 12.198 13.844 15.379 17.292 35.563 38.885 41.923 45.642 48.290 27 11.808 12.879 14.573 16.151 18.114 36.741 40.113 43.195 46.963 49.645 28 12.461 13.565 15.308 16.928 18.939 37.916 41.337 44.461 48.278 50.993 29 13.121 14.256 16.047 17.708 19.768 39.087 42.557 45.722 49.588 52.336 30 13.787 14.953 16.791 18.493 20.599 40.256 43.773 46.979 50.892 53.672 O Reject O Do not reject (2) O insufficient O sufficient (1) (3) O less than O greater than different from
1.
Consider the hypothesis statement to the right.
Но
2 5.0
State your conclusion given that s = 1.6, n= 25, and a = 0.05.
H,:o < 5.0
1 Click the icon to view a table of chi-square critical values.
Calculate the appropriate test statistic.
The test statistic is
(Round to two decimal places as needed.)
Determine the appropriate critical value(s).
The critical value(s) is(are)
(Round to three decimal places as needed. Use a comma to separate answers as needed.)
(1)
the null hypothesis. There is (2)
evidence that the population variance is (3)
5.0.
Transcribed Image Text:1. Consider the hypothesis statement to the right. Но 2 5.0 State your conclusion given that s = 1.6, n= 25, and a = 0.05. H,:o < 5.0 1 Click the icon to view a table of chi-square critical values. Calculate the appropriate test statistic. The test statistic is (Round to two decimal places as needed.) Determine the appropriate critical value(s). The critical value(s) is(are) (Round to three decimal places as needed. Use a comma to separate answers as needed.) (1) the null hypothesis. There is (2) evidence that the population variance is (3) 5.0.
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