Consider the heating curve provided for 1.00 mole of a substance that begins as a solid at -14.8 °C and ends as a gas at 121.1 °C. Specific heat capacities: solid = 145.6 J/mol·°C, liquid = 97.25 J/mol- °C, gas = 68.49 J/mol·°C %3D %3D

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Consider the heating curve provided for 1.00 mole of a substance that
begins as a solid at -14.8 °C and ends as a gas at 121.1 °C.
Specific heat capacities: solid = 145.6 J/mol·°C, liquid = 97.25 J/mol-
°C, gas = 68.49 J/mol·°C
%3D
%3D
Transcribed Image Text:Consider the heating curve provided for 1.00 mole of a substance that begins as a solid at -14.8 °C and ends as a gas at 121.1 °C. Specific heat capacities: solid = 145.6 J/mol·°C, liquid = 97.25 J/mol- °C, gas = 68.49 J/mol·°C %3D %3D
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Solution

From the heating curve, it is clear that the substance is solid at 14.8 ^{_{0}}C and the melting point of the substance is 4.1°C . The substance begins to melt at this temperature and temperature remains constant till the substance is completely converted to liquid. Once the liquifaction is complete, the temperature of the substance rises till its boiling point, 106.700 . The change of state from liquid to gas begins at this temperature and temperature remains constant till the substance is completely converted into gas. Once the vapourisation is complete temperature of the substance increases when heat is supplied.

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