Consider the half-reaction for the reduction of Cd2+ to Cd(s). Cd² + (aq) + 2 e¯ – Cd(s) = -0.403 V Calculate the potential of the cadmium electrode at 25 °C when immersed in a 0.0500 M solution of CdBr,. Eca = V

Consider the half-reaction for the reduction of Cd2+ to Cd(s). Cd² + (aq) + 2 e¯ – Cd(s) = -0.403 V Calculate the potential of the cadmium electrode at 25 °C when immersed in a 0.0500 M solution of CdBr,. Eca = V

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Electrolysis

Electrolysis is defined as the process of breaking down ionic compounds into their constituent elements by passing a direct electric current through the compound in a fluid state. The cathode reduces cations, while the anode oxidizes anions. An electrolyte, electrodes, and some form of external power source are the main components required for conducting electrolysis. A partition, such as an ion-exchange membrane or a salt bridge, may also be used, but this is optional. These are primarily used to prevent the products from diffusing near the opposing electrode.

Question

Consider the half-reaction for the reduction of Cd²+ to Cd(s).
Cd? + (aq) + 2 e- → Cd(s)
Ecgtica = -0.403 V
Calculate the potential of the cadmium electrode at 25 °C when immersed in a 0.0500 M solution of CdBr,.
Eca =
V
Calculate the potential of the cadmium electrode at 25 °C when immersed in a 0.0480 M NAOH solution that is saturated with
Cd(OH)2. The Ksp for Cd(OH), is 7.2 × 10-15.
Eca =
V
Calculate the potential of the cadmium electrode at 25 °C when immersed in a 0.0470 M Cd(NH,+ and 0.325 M NH, solution.
The B4 for Cd(NH,)?+ is 3.63 x 106.
Eca =
V

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