Consider the Haber process at 500 ºC: N, (g) + 3H, (g) =2NH; (g) with a AH of reaction equal to -92 kJ/mol. How would the equilibrium be influenced by each of the following changes? • Increasing the temperature – left, right, or no effect? • Increasing the volume – left, right, or no effect? • Increasing the pressure – left, right, or no effect?

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Consider the Haber process at 500 ºC: N, (g) + 3H, (g)=2NH; (g) with a AH of reaction equal to
-92 kJ/mol. How would the equilibrium be influenced by each of the following changes?
• Increasing the temperature - left, right, or no effect?
• Increasing the volume – left, right, or no effect?
• Increasing the pressure
• Adding He (g) to the system – left, right, or no effect?
• Adding N2 (g) to the system - left, right, or no effect?
• Adding catalytic Pt (s) to the system – left, right, or no effect?
- left, right, or no effect?
Below is a hypothetical reaction and a table showing the initial concentrations of substances in the
reaction. If x represents the increase in the concentration of A as the reaction gets to equilibrium,
which of these expressions would you use to solve for x?
A
+
B
20
initial:
2
10
K= (10 – 2x)*/x(2+x)
= (10 + 2x)*/x(2+x)
K= (10 – 2x)*/2x
K= (10 – x)*/x(2+x)
Transcribed Image Text:Consider the Haber process at 500 ºC: N, (g) + 3H, (g)=2NH; (g) with a AH of reaction equal to -92 kJ/mol. How would the equilibrium be influenced by each of the following changes? • Increasing the temperature - left, right, or no effect? • Increasing the volume – left, right, or no effect? • Increasing the pressure • Adding He (g) to the system – left, right, or no effect? • Adding N2 (g) to the system - left, right, or no effect? • Adding catalytic Pt (s) to the system – left, right, or no effect? - left, right, or no effect? Below is a hypothetical reaction and a table showing the initial concentrations of substances in the reaction. If x represents the increase in the concentration of A as the reaction gets to equilibrium, which of these expressions would you use to solve for x? A + B 20 initial: 2 10 K= (10 – 2x)*/x(2+x) = (10 + 2x)*/x(2+x) K= (10 – 2x)*/2x K= (10 – x)*/x(2+x)
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