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Consider the graph to the right. ... Suppose you needed to dilate this figure on the ... same coordinate plane. Which of these dilations would create the largest possible image that could fit on a new coordinate plane which only covered-5 < x < 5 and -5 < y s 5?

Consider the graph to the right. ... Suppose you needed to dilate this figure on the ... same coordinate plane. Which of these dilations would create the largest possible image that could fit on a new coordinate plane which only covered-5 < x < 5 and -5 < y s 5?

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Consider the graph to the right. A(-4, 8) B (6, 7) Suppose you needed to dilate this figure on the 6- same coordinate plane. Which of these dilations 4- would create the largest possible image that could fit on a new coordinate plane which only D(-6, 1) covered-5 <x < 5 and -5 < y< 5? -8 -6 -4 6. C (4,–2) O Do.625 because on the pre-image, A(-4, 8) is the point that is farthest outside of the -5 to 5 boundary due to the y = 8 coordinate, and 5/8 is 0.625. O D16 because on the pre-image, A(-4, 8) is the point that is farthest outside of the -5 to 5 boundary due to the y = 8 coordinate, and 8/5 is 1.6. O Do 833 because on the pre-image, D(-6, 1) is the point that is closest to the -5 to 5 boundary due to the x = -6 coordinate, and -5/-6 is 0.833. O D1.2 because on the pre-image, D(-6, 1) is the point that is closest to the -5 to 5 boundary due to the x = -6 coordinate, and -6/-5 is 1.2.
Transcribed Image Text:Consider the graph to the right. A(-4, 8) B (6, 7) Suppose you needed to dilate this figure on the 6- same coordinate plane. Which of these dilations 4- would create the largest possible image that could fit on a new coordinate plane which only D(-6, 1) covered-5 <x < 5 and -5 < y< 5? -8 -6 -4 6. C (4,–2) O Do.625 because on the pre-image, A(-4, 8) is the point that is farthest outside of the -5 to 5 boundary due to the y = 8 coordinate, and 5/8 is 0.625. O D16 because on the pre-image, A(-4, 8) is the point that is farthest outside of the -5 to 5 boundary due to the y = 8 coordinate, and 8/5 is 1.6. O Do 833 because on the pre-image, D(-6, 1) is the point that is closest to the -5 to 5 boundary due to the x = -6 coordinate, and -5/-6 is 0.833. O D1.2 because on the pre-image, D(-6, 1) is the point that is closest to the -5 to 5 boundary due to the x = -6 coordinate, and -6/-5 is 1.2.
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