Consider the graph of y=g(x). Graph attached below. List the following in ascending order(lowest to highest). a) g'(−3) b) g'(−2) c) g'(−1) d) g'(2)

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Consider the graph of  y=g(x). 

Graph attached below.

List the following in ascending order(lowest to highest).

  a) g'(−3)       b) g'(−2)      c) g'(−1)         d) g'(2) 

---

**Consider the graph of \( y = g(x) \).**

![Graph]

The graph depicts the function \( g(x) \) and includes the following points of interest:

- X-axis ranges from \(-4\) to \(4\).
- Y-axis ranges from \(-2\) to \(2\).

### Key Plot Points:
- The curve starts at approximately \(( -4, 0.5 )\), reaches a peak just above \(1\) at around \(x = -3\), and then descends crossing the x-axis between \(-2\) and \(-1\).
- The curve reaches its lowest point just below \(-1\) at about \(x = -1\), then ascends, crossing the x-axis again around \(x = 1\).
- The graph appears to linearly increase from \(x = 2\) onward past \(y = 1\).

---

**Problem Statement**

List the following derivatives in ascending order (lowest to highest):

a) \(g'(-3)\)

b) \(g'(-2)\)

c) \(g'(-1)\)

d) \(g'(2)\)

**_Write your answer as a, d, c, b or b, d, a, c, etc._**

**Answer Box:**

---

**Graph Analysis for Derivatives:**
To determine the derivatives \(g'(x)\) at the given points, consider the slope of the tangent to the curve at those points:

- **\(g'(-3)\)**: The slope here is negative, as the curve descends.
- **\(g'(-2)\)**: The slope is zero, as the curve reaches a trough or flat point.
- **\(g'(-1)\)**: The slope here will be positive, as the curvature starts ascending.
- **\(g'(2)\)**: The slope will be positive and likely constant as the curve forms a linear shape.

### Derivatives Evaluation:
- \(g'(-3)\): Negative slope.
- \(g'(-2)\): Zero slope.
- \(g'(-1)\): Positive slope.
- \(g'(2)\): Positive slope (likely higher than at \(x = -1\)).

By visually analyzing the slopes:

- **Order from lowest to highest slope:**
  - Most negative: \(g'(-3)\)
  - Zero: \(
Transcribed Image Text:--- **Consider the graph of \( y = g(x) \).** ![Graph] The graph depicts the function \( g(x) \) and includes the following points of interest: - X-axis ranges from \(-4\) to \(4\). - Y-axis ranges from \(-2\) to \(2\). ### Key Plot Points: - The curve starts at approximately \(( -4, 0.5 )\), reaches a peak just above \(1\) at around \(x = -3\), and then descends crossing the x-axis between \(-2\) and \(-1\). - The curve reaches its lowest point just below \(-1\) at about \(x = -1\), then ascends, crossing the x-axis again around \(x = 1\). - The graph appears to linearly increase from \(x = 2\) onward past \(y = 1\). --- **Problem Statement** List the following derivatives in ascending order (lowest to highest): a) \(g'(-3)\) b) \(g'(-2)\) c) \(g'(-1)\) d) \(g'(2)\) **_Write your answer as a, d, c, b or b, d, a, c, etc._** **Answer Box:** --- **Graph Analysis for Derivatives:** To determine the derivatives \(g'(x)\) at the given points, consider the slope of the tangent to the curve at those points: - **\(g'(-3)\)**: The slope here is negative, as the curve descends. - **\(g'(-2)\)**: The slope is zero, as the curve reaches a trough or flat point. - **\(g'(-1)\)**: The slope here will be positive, as the curvature starts ascending. - **\(g'(2)\)**: The slope will be positive and likely constant as the curve forms a linear shape. ### Derivatives Evaluation: - \(g'(-3)\): Negative slope. - \(g'(-2)\): Zero slope. - \(g'(-1)\): Positive slope. - \(g'(2)\): Positive slope (likely higher than at \(x = -1\)). By visually analyzing the slopes: - **Order from lowest to highest slope:** - Most negative: \(g'(-3)\) - Zero: \(
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