Consider the graph below for a firm. At point T, we know that the firm K TC = Total Cost; Q=f(K, L); 100 70 Q, =100 TC, 60 80 A. Is a cost minimizer but not technical efficient. B. Is a cost minimizer. C. Is technical inefficient and a not a cost minimizer. D. Is technical efficient but not a cost minimizer. E. None of the above.
Consider the graph below for a firm. At point T, we know that the firm K TC = Total Cost; Q=f(K, L); 100 70 Q, =100 TC, 60 80 A. Is a cost minimizer but not technical efficient. B. Is a cost minimizer. C. Is technical inefficient and a not a cost minimizer. D. Is technical efficient but not a cost minimizer. E. None of the above.
Chapter1: Making Economics Decisions
Section: Chapter Questions
Problem 1QTC
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Transcribed Image Text:The graph represents a firm's cost function, illustrating the relationship between total cost (TC), capital (K), and labor (L) for producing a given quantity (Q). The curve marked \( Q_1 = 100 \) indicates an isoquant, showing all combinations of K and L that yield 100 units of output. The line labeled \( TC_1 \) represents an isocost line, showing all combinations of K and L that result in the same total cost.
Key Points on the Graph:
- **Point T**: Located at the higher level of K and intersects the isoquant \( Q_1 = 100 \).
- **Point E**: Represents an equilibrium where the isocost line is tangent to the isoquant, indicating both technical and cost efficiency.
- **Point U**: It illustrates a different combination of K and L.
Multiple Choice Question:
At point T, we must evaluate the firm's cost-efficiency and technical efficiency. The options are:
- **A**: Is a cost minimizer but not technically efficient.
- **B**: Is a cost minimizer.
- **C**: Is technically inefficient and not a cost minimizer.
- **D**: Is technically efficient but not a cost minimizer.
- **E**: None of the above (correct answer).
Analysis:
Point T does not lie on the isocost line tangent to the isoquant, suggesting it is neither a cost minimizer nor technically efficient. Therefore, the correct answer is **E: None of the above**.
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