Consider the given table, compute P45 *Classintervalffxd.fdcf s34 - 52443172-4-16453 - 71362186-3-972 - 9081405-2-101291 - 109121001200-1-1224110 - 12826119309450129 - 1471384141353148 - 166615794221259167 - 185117617660fdN =60658929126.19126.3195.25110.46

Given that We have to find percentage of 45:

Answered: Consider the given table, compute P45 *…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Here is a data set: Construct a grouped frequency distribution table (GFDT) for this data set. You want 10 classes with a "nice" class width. Your classes should be labeled using interval notation. Each class contains its lower class limit, and the lower class limits should all be multiples of the class width. In that the data appears to be discrete, use a closed-interval to label each class. Data range [378,402] 403,427] 428,452] 453,477] [478,502] [503,527] [528,552] [553,577] [578,602] [603,627] X X 2 X 5 X Frequency 1 X 1 X X 3 7 X X 2 6 X X 0 549 406 487 518 445 620 378 468 558 525 499 521 444 479 537 486 491 411 545 549 529 489 484 448 448 556 532 431 X
For the following frequency table, midpoint and relative frequency of the second class, class width and fourth actual class respectively are: Class f [30 – 39] 12 [40 – 49] [50 – 59] [60 – 69] [70 – 79] 8. 1 7 10 O 44.5,0.211, 9 and [59.5 69.5] O 44.5 , 0.211, 10 and [60.5 - 69.5] O 4.5 , 0.211, 10 and [59.5 69.5] O 4.5,0.211, 10 and [59.5 70.5] O 45,0.211, 10 and [59.5 69.5]
I need answer within 20 minutes please please with my best wishes
What is the class mark for a class interval of 19.50—22.50?
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A CFO is looking at what percentage of a company's resources are spent on computing. He samples companies in the pharmaceutical industry and develops the following stem-and-leaf display (leaf unit = 0.1). 5. 255568999 269 9. 7. 11224557789 001222458 6. 8. 02455679 10 1556 11 137 12 13 255 What would be the first class interval for the frequency histogram? a. 5.2 < 6.6 O b. 5.0 < 6.0 O c. 5.0 < 6.4 O d. None of the suggested answers are correct e. 5.2 < 6.0
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Calculate Semi-Inter-Quartile Range and its Co-efficient of Q.D. from the following Vata : Marks 0-10 10-20 20-30 30-40 40-50 50-60 60-70 70-80 80-90 No. of Students 11 18 25 28 30 33 22 15 22
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From the following data calculate Harmonic mean : Class Interval Frequency 0-10 20 10-20 25 20-30 85 30-40 72 40-50 90 50-60 130 60-70 60 )
Five different oat varieties were planted in each of the four fields.The following crops were obtained oat variety field field field field 1 2 3 4 1 296 357 340 348 2 402 390 420 335 3 345 324 358 308 4 360 322 336 270 5 324 339 357 308 Test whether there is a difference in the amount of harvest based on the data(a) between fields. (b) between varieties. DO NOT use ready-made functions of R or any other software for tests. Instead, you can use R to calculate quantiles, sample means, sample standard deviations and p-values. If no significance level is given in the task, use the usual/usual significance levels.

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