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Consider the given isosceles triangle of base 12 and edges / side lengths x. If x is increasing at the rate of 4 in/min what rate is the triangle's area changing when x = 15 inches? solution: dx dt A= bh A. (12) h A: 6h = 4 in/min. > choices = +2 dA X DA dt dA at = 4 X T in x 17 dh dt (2011) 40 7 6²+h²=x² a) 26.19 in²/min ✓ b) 24.12 in²/min. 29.18 in ³ /min d) 18.13 in ³/min h²=x²-36 bhah x d 321 (h) 15 (4) = 20√ 21 21 dh dt in²/min = 26.19 in ² / min 2 X = 15 36th ² = 225 h² = 189 h = 3√21

Consider the given isosceles triangle of base 12 and edges / side lengths x. If x is increasing at the rate of 4 in/min what rate is the triangle's area changing when x = 15 inches? solution: dx dt A= bh A. (12) h A: 6h = 4 in/min. > choices = +2 dA X DA dt dA at = 4 X T in x 17 dh dt (2011) 40 7 6²+h²=x² a) 26.19 in²/min ✓ b) 24.12 in²/min. 29.18 in ³ /min d) 18.13 in ³/min h²=x²-36 bhah x d 321 (h) 15 (4) = 20√ 21 21 dh dt in²/min = 26.19 in ² / min 2 X = 15 36th ² = 225 h² = 189 h = 3√21

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
Consider the given isosceles triangle of base 12 and edges / side lengths x. If x is increasing at the rate of 4 in/min what rate is the triangle's area changing when x = 15 inches? LABE solution: X A = = bh A = 1/2 (12) h A= uh dx dt = 4in/min. DA dt X 12- dA वर DA dt X dA dt = 6 in x 17 áh dt (2014) 402 7 6² +h²=x² h²= x²-36 bhdha = 2x d वर choices = a) 26.11 in ² / min ✓ b) 24.12 in ² / min. c) 29.18 in ³ /min +3 d) 18.13 in ² /min dh 3√21 (d 2 ) = 15 = dh dt in ³ / min = 26.19 in ¹/min Cabutin 15 (4) 20√21 21 X = 15 36th ² = 225 h² = 189 h = 3√₂
Transcribed Image Text:Consider the given isosceles triangle of base 12 and edges / side lengths x. If x is increasing at the rate of 4 in/min what rate is the triangle's area changing when x = 15 inches? LABE solution: X A = = bh A = 1/2 (12) h A= uh dx dt = 4in/min. DA dt X 12- dA वर DA dt X dA dt = 6 in x 17 áh dt (2014) 402 7 6² +h²=x² h²= x²-36 bhdha = 2x d वर choices = a) 26.11 in ² / min ✓ b) 24.12 in ² / min. c) 29.18 in ³ /min +3 d) 18.13 in ² /min dh 3√21 (d 2 ) = 15 = dh dt in ³ / min = 26.19 in ¹/min Cabutin 15 (4) 20√21 21 X = 15 36th ² = 225 h² = 189 h = 3√₂
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