Consider the given isosceles triangle of base 12 and edges / side lengths x. If x is increasing at the rate of 4 in/min what rate is the triangle's area changing when x = 15 inches? solution: dx dt A= bh A. (12) h A: 6h = 4 in/min. > choices = +2 dA X DA dt dA at = 4 X T in x 17 dh dt (2011) 40 7 6²+h²=x² a) 26.19 in²/min ✓ b) 24.12 in²/min. 29.18 in ³ /min d) 18.13 in ³/min h²=x²-36 bhah x d 321 (h) 15 (4) = 20√ 21 21 dh dt in²/min = 26.19 in ² / min 2 X = 15 36th ² = 225 h² = 189 h = 3√21

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