Consider the given circuit. b 2 n V₁ bn Rw ww an 12+ Rw a C B Zp Zp Rw ww Zp Each load is composed of a 1.5 H inductor in parallel with a 100 μF capacitor and a 1,030 resistor. The resistance is labeled Rw =0 Q. Use positive phase sequence with Vab= 11520° V at f= 60 Hz. Please report your answer, so the magnitude is positive, and all angles are in the range of negative 180 degrees to positive 180 degrees. etermine the rms line current and the total power delivered to the load. (Round the final answers to three decimal places.) he rms line current is 0.132 * A. he total power delivered to the load is 12.740 W.
Consider the given circuit. b 2 n V₁ bn Rw ww an 12+ Rw a C B Zp Zp Rw ww Zp Each load is composed of a 1.5 H inductor in parallel with a 100 μF capacitor and a 1,030 resistor. The resistance is labeled Rw =0 Q. Use positive phase sequence with Vab= 11520° V at f= 60 Hz. Please report your answer, so the magnitude is positive, and all angles are in the range of negative 180 degrees to positive 180 degrees. etermine the rms line current and the total power delivered to the load. (Round the final answers to three decimal places.) he rms line current is 0.132 * A. he total power delivered to the load is 12.740 W.
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Transcribed Image Text:### Circuit Analysis
**Given Circuit Diagram:**
The diagram shows a three-phase circuit with two parallel branches connected between points C-N and N-A and N-B. Each branch consists of a complex load represented by \( Z_p \).
**Component Details:**
- **Loads:** Each load comprises:
- A 1.5 H inductor
- A 100 µF capacitor
- A 1,030 Ω resistor in parallel
- **Resistance \( R_w \):** 0 Ω
- **Voltage Source:** \( V_{ab} = 115\angle0^\circ \) V at frequency \( f = 60 \) Hz
**Instructions:**
- Use a positive phase sequence for calculations.
- Report magnitudes as positive, and angles between -180° to +180°.
**Tasks:**
- **Determine:**
- **RMS Line Current**
- Result: \( 0.132 \) A
- **Total Power Delivered to the Load**
- Result: \( 12.740 \) W
**Analysis Explanation:**
- The network is evaluated to find the root mean square (RMS) line current and power, critical for understanding load characteristics in AC circuits.
- Calculations involve converting the given circuit into impedance forms and using phasors for AC analysis.
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