Consider the function QA1P05 D7E3IJOA1P05 D7E3 f(2) = { if 0 < z < 3 | æ² – 5 if 3 < x Now let QA1P05 D7E QA1P05D7E3IJO P05 D7E QA1P05D7E3IJO g(x) = f(1) dt. Calculate A1P05 D7 IP05 a) g(2) =| JOA1P05D7E3IJOAIR b) g'(2) = |

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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BIJOA1P05 D7
D7E3IJQA1P05 D7E3IJOA1P05D7E3IJE) = {-5 f 3 < z
D7E3IJQA1P05 D7E3IJOAIP05 D7E3IJO
JOA1P05 D7E31
Consider the function
S 4
0<z < 3
Now let
D7E3IJQA1P05 D7E3IJOA1P05 D7E3IJO
g(x) =
f(t) dt.
Calculate
AIP05 D7E3IJQA1P05 D7E3IJQA1P05
a) g(2) =
3IJOAIP05 D7E3IJQA1P05
b) g'(2) =|
Transcribed Image Text:BIJOA1P05 D7 D7E3IJQA1P05 D7E3IJOA1P05D7E3IJE) = {-5 f 3 < z D7E3IJQA1P05 D7E3IJOAIP05 D7E3IJO JOA1P05 D7E31 Consider the function S 4 0<z < 3 Now let D7E3IJQA1P05 D7E3IJOA1P05 D7E3IJO g(x) = f(t) dt. Calculate AIP05 D7E3IJQA1P05 D7E3IJQA1P05 a) g(2) = 3IJOAIP05 D7E3IJQA1P05 b) g'(2) =|
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